I need to use factoring to solve the equation 9x^2 + 27 x = 0 I think the answer is x = 3, and x = -3 but I am not sure can you please help?
2007-06-07 13:15:04 · 4 answers · asked by ambi565 2 in Science & Mathematics ➔ Mathematics
Close... it's x = -3 or x = 0. Here's how:
9x² + 27x = 0. These terms have a common factor of 9x.
9x(x + 3) = 0. From the zero-product property, either of these factors could be 0. Solve for each.
9x = 0 or x + 3 = 0.
If 9x = 0, dividing by 9 leaves x = 0.
If x + 3 = 0, adding -3 gives x = -3.
2007-06-07 13:23:00 · answer #1 · answered by Anonymous · 0⤊ 0⤋
= (9x) * (x+3) = 0
x=0 x= -3
If you plug in x=3, the equation does not work.
2007-06-07 20:25:57 · answer #2 · answered by Mortal 1 · 0⤊ 0⤋
When in doubt, substitute the values of x into the equation. I think x=3 is NOT a solution.
2007-06-07 20:29:09 · answer #3 · answered by cattbarf 7 · 0⤊ 0⤋
9x^2+27=0
9x(x+3)=0
9x=0
x=0
x+3=0
x=-3
2007-06-07 23:13:32 · answer #4 · answered by sam 3 · 0⤊ 0⤋