Simplify.
2007-06-07 12:14:58 · 7 answers · asked by Adam T 1 in Science & Mathematics ➔ Mathematics
[4/(x^2-x)] + [4/(x+1)]
=4/(1/x(x-1)+1/(x-1))
=4/(x-1)(1/x+1)
=4(x+1)/x(x-1)
2007-06-07 12:21:59 · answer #1 · answered by Hang 3 · 0⤊ 0⤋
I believe the answer would be 4(x^2-x +1x+1)/x^3-x +x^2-x
find the common denominator.
2007-06-07 19:24:45 · answer #2 · answered by Anonymous · 0⤊ 0⤋
= [4(x+1) / (x^2-x)(x+1)] + [4(x^2-x) / (x^2-x)(x+1)]
= [4(x+1) + 4(x^2-x)] / (x^2-x)(x+1)
= (4x+4+4x^2-4x) / (x^2-x)(x+1)
= 4(x^2+1) / x(x+1)(x-1)
2007-06-07 19:33:07 · answer #3 · answered by Anonymous · 0⤊ 0⤋
4 / x.(x - 1) + 4 / (x + 1)
(4x + 4 + 4x² - 4x) / [ x.(x - 1).(x + 1) ]
= (4x² + 4) / [ x.(x - 1).(x + 1) ]
= 4.(x² + 1) / [ x.(x - 1).(x + 1) ]
2007-06-08 03:32:54 · answer #4 · answered by Como 7 · 0⤊ 0⤋
[4/(x^2-x)]+[4/(x+1)] = [4/x(x-1)] + [4/(x+1)]
= [4(x+1) +4x(x-1)]/(x(x-1)(x+1)
= [4x +4 + 4x^2-4x ]/ x(x^2-1)
= 4(1+x^2)/x(x^2-1)
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2007-06-07 19:25:37 · answer #5 · answered by Anonymous · 0⤊ 1⤋
[4/(x^2-x)] + [4/(x+1)] = [4/x(x-1)] + [ 4/(x+1)]
= 4(x+1) + 4*x*(x-1)
---------------------------
x (x-1)(x+1)
= 4x + 4 +4x^2 -4x
-----------------------
x(x-1)(x+1)
= 4(x^2 + 1)
---------------
x(x^2-1)
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2007-06-07 19:36:39 · answer #6 · answered by Aruldass Classof1 1 · 0⤊ 0⤋
its called, putting that in the calculator. It take like 10 seconds then boom. you have an answer. at least if you have a graphing calculator
2007-06-07 19:18:58 · answer #7 · answered by Gravenimage 3 · 0⤊ 1⤋