Hmm.
x^2 + 144 = 0
So
x^2 = -144
x = sqrt(-144)
x = 12i (where "i" is the imaginary number where i^2=-1)
2007-06-07 11:55:04
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answer #1
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answered by davidbgreensmith 4
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x^2 + 144 = 0
x = ± 12i
12i² = -144
-144 + 144 = 0
2007-06-07 21:27:55
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answer #2
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answered by UNIQUE 3
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x^2 + 144 = 0
x = ± 12i
12i² = -144
-144 + 144 = 0
2007-06-07 18:54:13
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answer #3
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answered by Robert L 7
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so...
2x+144=0
-144 (you need to move 144 to the other side because you cannot have a real number and a variable on the same side...to move144 to the other side you subtract it from both sides and therefore canceling it from the left side resulting in
-144 on the opposing side)
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2x= -144 (now divide 2 on both side so it cancels out the 2 on the left and -144 divided by 2 is -72 )
so....
x= -72
check: -72 x 2= -144
hope this helps =)
2007-06-07 19:01:44
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answer #4
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answered by Anonymous
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10 points? Really? Everyone else only gives 8.
x^2 + 144 = 0
x^2 = -144
x = square root(-144) = 12 i
2007-06-07 18:54:47
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answer #5
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answered by DanE 7
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x²+144=0
x²=-144
x=±12 i
(12i)²+144=0
-144+144=0
0=0
(-12i)²+144=0
-144+144=0
0=0
2007-06-07 18:59:25
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answer #6
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answered by yupchagee 7
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12 * 12 = 144
check
x^2 + 144 = 0
- 144 - 144
x^2 = -144
square root both (DONT KNOW SYMBOL)
X = 12i (i=imaginary number)
2007-06-07 18:57:24
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answer #7
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answered by Luis B 2
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this quadratic does not have real roots, the roots are 12i and -12i where i=sqrt(-1)
substitute 12i, 144i^2+144=-144+144=0
for -12i, (-12i)(-12i)+144=144i^2+144=-144+144=0
2007-06-07 18:57:26
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answer #8
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answered by careyschwartz 2
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x^2 + 144 = 0
x^2 = -144
x = +/- sqrt(-144)
x = +/- 12sqrt(-1)
x = +/- 12i
2007-06-07 18:55:51
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answer #9
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answered by hawkeye3772 4
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x^2+144=0
x^2+144-144 = 0-144
x^2 = -144
Apply Square root on both sides.
Sqrt(x^2)=Sqrt(-144)
Sqrt(x^2)=Sqrt(144*-1)
Sqrt(x^2)=Sqrt(144*i^2)
x=12i
The answer is 12i.
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2007-06-07 19:09:13
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answer #10
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answered by kiran p 1
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