avogadro problem?

Question

given the equation for the reaction H2+Cl2-->2HCL,
how many grams of HCl will be formed from 2.00 liters of chlorine at STP.

what steps would you take to solve this problem?

Answer 1

2/22.4 is the moles of Cl2.

Double this number of moles of HCl will form.

Then multiply by 36.5, the Mr of HCl.

Answer 2

First we calculate the number of moles of Cl2 present in 2 lts
at STP,according to Avagadro one mole of any gas occupies 22.4 lts at STP thus we can say
1.00moleCl2
----------- 2.00 ltr = 0.0892mole Cl2
22.4ltr
0.0892 moles of chlorine is present in 2.00 ltr.

The balanced chemical equation shows one mole of chlorine gives two moles of HCl,now we have to calculte how many moles of HCl is produced from 0.0892 moles of chlorine
this is calculated as follows
2mole HCl
__________ 0.0892 mole Cl2 = 0.1784mole HCl
1 mole Cl2
formula mass of HCl is 36.5gms
we have to calculate of HCl produced in grams ,so we need to convert moles into grams
36.5gms
_________0.1784mol HCl = 6.51gms HCl
1 mole HCl
from the above calculatios we found that 6.51gms of HCl can be produced from 2.00lts of chlorine.
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Answer 3

First.We know that in STP 1mol=22.4Liter so multiply 2litre ba1/22.4 it will give u the mol of Cl2
Second.Based on the formula every 1mol Cl2 gives 2mol HCL so multiply the number given from step 1 by 2
Third.now you have the mol HCL just multiply by 36.5 and it will give u the final answer