If ax = b - cx, then x =
b / a+c
b-c / a
b/a -c
b/ac
2007-06-07 09:09:09 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Whenever you have more than one x, put all of the xs on one side and all of the non-xs on the other:
ax + cx = b (add cx to both sides)
Now factor out the x from the left side:
x * (a + c) = b
And divide both sides by (a+c):
x = b/(a+c)
Therefore, your first answer is correct.
2007-06-07 09:15:32 · answer #1 · answered by kittsil 2 · 0⤊ 0⤋
ax=b-cx
so ax + cx = b
x is common to both so
x (a + c) = b
then
x= b/(a+c)
2007-06-07 16:13:57 · answer #2 · answered by Anonymous · 0⤊ 0⤋
ax = b - cx
Add cx:
ax + cx = b
Factorise LHS:
(a + c)x = b
Divide by a + c:
x = b / (a + c).
2007-06-07 16:12:50 · answer #3 · answered by Anonymous · 0⤊ 0⤋
ax = b - cx
ax + cx = b
x( a + c ) = b
x = b / ( a + c )
2007-06-07 16:13:38 · answer #4 · answered by muhamed a 4 · 0⤊ 0⤋
ax = b - cx
ax + cx = b
x(a + c) = b
x = b/a+c
Hope I helped!
2007-06-07 16:17:44 · answer #5 · answered by Buttons 3 · 0⤊ 0⤋
x=b/(a+c) if a+c#0
2007-06-07 16:17:14 · answer #6 · answered by ♥*´`*•.katie.•*´`*♥ 2 · 0⤊ 0⤋
ax+cx = b
x (a+c) = b
x= b/(a+c)
2007-06-07 16:12:38 · answer #7 · answered by chess2226 3 · 1⤊ 0⤋
X=B/A+C
2007-06-07 16:18:09 · answer #8 · answered by srdongato2 5 · 0⤊ 0⤋
b/a+c
2007-06-07 16:12:58 · answer #9 · answered by Anonymous · 0⤊ 0⤋
b/(a+c).answer
2007-06-07 16:22:02 · answer #10 · answered by Anonymous · 0⤊ 0⤋