how much energy must be added to 50 grams of water at 50 degrees Celsius to convert it to steam?

Answer 1

sure

Answer 2

First you need to heat it to 100°C, then to evaporate it.

The small calorie or gram calorie approximates the energy needed to increase the temperature of 1 gram of water by 1 °C. This is about 4.184 Joules.

It takes 2,260 Joules (540 calories) of heat energy to evaporate 1 gram of water at 100° C (212° F) at sea level.

50*(100-50)*4.184 + 50*2260 = 123460 Joules

this is about the amount of energy of raising 200 pounds 500 feet high. Or another way to put it: if a guy fall from a 50-story building, the amount of energy dissipated when he hits the ground is enough to heat and evaporate 50g of water.

Answer 3

1 calorie raises 1 gram of water 1 degree celsius. so 50 * 50 = 2500 calories will raise the water to 100 degrees celsius. the boiling point.

Answer 4

First raise the temperature by another 50C to boiling (100C):

50gH2O x 50C x 1cal/g-C = 2500 cal

Next boil the water:

50gH2O x 540cal/g = 29,500

Add them up:

27,000 + 50 = 27,050cal

One point of this homework is seeing how enormous is the latent heat of vaporization of water.

Answer 5

Are you at sea level?