A. True
B. False
2007-06-07 07:24:51 · 6 answers · asked by Lizza C 1 in Science & Mathematics ➔ Mathematics
true.......
d=sqrt( b^2-4ca)
so if b^2 -4ac is -ve then how can you take the sqrt.. the root would be imaginary......
2007-06-07 07:28:59 · answer #1 · answered by Anonymous · 0⤊ 0⤋
B. False
A negative discriminant means there are the traditional two solutions (even x = 0 is really x = 0 AND x = 0), but also means that they are complex numbers. (Numbers that look something like: 5 + 6i. Technically, even "real" solutions (positive discriminant) are complex numbers, but their "i" portion is 0i: 5 + 0i = 5.)
2007-06-07 14:33:58 · answer #2 · answered by roynburton 5 · 0⤊ 0⤋
It depends. There are no real solutions to the equation. However, if you allow complex solutions with imaginary numbers, then there are solutions.
2007-06-07 14:33:13 · answer #3 · answered by RG 3 · 0⤊ 0⤋
If the answer requires real numbers it´s true
If you admit complex number solutions it´s false.
2007-06-07 14:30:20 · answer #4 · answered by santmann2002 7 · 0⤊ 0⤋
true, thats because you cant square root a negative number when you use the general formula
2007-06-07 14:27:22 · answer #5 · answered by davin 2 · 0⤊ 0⤋
There are no _real_ solutions
2007-06-07 14:29:23 · answer #6 · answered by dogsafire 7 · 0⤊ 0⤋