The question is: Find (a) the vertex of its graph, (b) its domain, and (c) its range
F(x)= x(squared)-2x-5
2007-06-07 06:41:46 · 4 answers · asked by alwayz_smilin_8012 2 in Science & Mathematics ➔ Mathematics
x^2-2x-5=(x-1)^2 -6
so the vertex is (1,-6),the domain is all real numbers and range
y>=-6 as to -6 you sum a positive number(x-1)^2
2007-06-07 06:48:32 · answer #1 · answered by santmann2002 7 · 0⤊ 0⤋
F(x) = x^2 - 2x -5 = (x - 1)^2 - 6
Therefore, as you can see, the vertex is at (1, -6)
The minimum of the graph is when x = 1, and its minimum value is -6.
2007-06-07 13:50:01 · answer #2 · answered by talr 4 · 0⤊ 0⤋
(a) V = (-b/2a, F(-b/2a)) = (1, -6).
(b) Unless otherwise noted in the problem, polynomials are defined over all reals.
(c) V is the minimum since a > 0, so F(x) ranges from -6 to positive infinity.
2007-06-07 13:46:31 · answer #3 · answered by TFV 5 · 0⤊ 0⤋
a. differentiate the equation and let it be zero, then find the value of x and y at that point
b. is it negative infinite to positive infinite? not sure abt this
c. from the vertex to positive infinite
2007-06-07 13:47:33 · answer #4 · answered by Alhazi 2 · 0⤊ 0⤋