OMG OMG! i NEED HELP!?

Question

am i doing these right?



7x² - 7x - 2x + 2 = 0
7x(x-2+2)=0
(7x-2)(x+2)

{2/7,2}?



4: 6x2 - 2 = x

6x(sq)-2=x
6x(sq)-2+x=0
x(6-2)(x+1)=0

{4,1}



5: x2 - x = 42

x(sq)-x+42=0
(x-1)(x+42)

{7,-6}






8: 3x² - 2x - 5 = 0

x(3x-2-5)=0
(3-2)(x-5)

{1,5}


And these- (that have the number in front of the varible-- how do i
solve them?? Do i follow the same procedure?)




9: 2a² - 9a = 5






10: 33x² - x - 14 = 0




11: 21x² + 22x - 24 = 0




12: 2x2 + 2x = 60




13: x2 + 16x + 48 = 0




14: x3 - x2 - 12x = 0



15: 4x² + 8x + 4 = 0

Answer 1

7x² - 7x - 2x + 2 = 0
7x²-9x+2=0 (combine like terms)
(7x-2)(x-1)=0
x=2/7,1

4. 6x² - 2 = x
6x²-x-2=0 (move the x over and change signs)
Use quadratic
(1+-sqrt(1+48))/12
(1+-7)/12
x=2/3 and -1/2

5. x² - x = 42
x²-x-42=0 (move 42 over)
(x-7)(x+6)=0
x=7, -6 You got that one right, but you did it wrong

8. 3x² - 2x - 5 = 0
(3x-5)(x+3)=0
x=5/3 and -3

Do these the same way I did the ones before, use quadratic if necessary
9: 2a² - 9a = 5
2a^2-9a-5=0
(2a+1)(a-5)
a=-1/2 and 5

Good luck

Answer 2

7x² - 7x - 2x + 2 = 0
7x(x-2+2)=0
(7x-2)(x+2)

{2/7,2}?

No. That is not the way.
7x² - 7x - 2x + 2 = 0 can be written as

7x( x - 1) - 2 ( x + 1) = 0 but since the factors inside the brackets are not same, you cannot do further simplification.

Best is to use quadratic formula.

7x^2 - 7x - 2x + 2 = 7x^2 - 9x + 2 = 0 and we have a = 7, b = -9 and c = +2 in the quadratic equation.

x =[ -b + or - sqrt (b^2 - 4ac) ] / 2a

= 9 + sqrt (91 - 56) / 14 = (9 + sqrt 35) / 28 and

(9 - sqrt. 35) / 28









4: 6x2 - 2 = x

6x(sq)-2=x
6x(sq)-2+x=0
x(6-2)(x+1)=0

{4,1}

Wrong.

6x^2 -x - 2 = 0 is the correct form and again you can apply the quadratic formula.



5: x2 - x = 42

x(sq)-x+42=0
(x-1)(x+42)

{7,-6}

Wrong.





8: 3x² - 2x - 5 = 0

x(3x-2-5)=0
(3-2)(x-5)

{1,5}

Again wrong.


And these- (that have the number in front of the varible-- how do i
solve them?? Do i follow the same procedure?)




9: 2a² - 9a = 5

2a^2 - 9a - 5 = 0 is a standard form of quadratic equation.






10: 33x² - x - 14 = 0




11: 21x² + 22x - 24 = 0




12: 2x2 + 2x = 60




13: x2 + 16x + 48 = 0




14: x3 - x2 - 12x = 0



15: 4x² + 8x + 4 = 0

can be written as x^2 + 2x + 1 =0 by dividing by 4

(x + 1)^2 = 0 and x = - 1 is the solution

Answer 3

no, i made some simple errors-
ex-
the first one you didnt add the common numbers together
the 1st line should become 7x² - 9x + 2 = 0
and do the quadratic formula from there.

4: 6x2 - 2 = x
should be 6x^2 -x -2=0 and use quad. formula

x2 - x = 42
==> x^2 -x -42=0 and this becomes (x-7)(x+6)=0 and
then x= 7, x=-6

and so on.

Answer 4

The first one is wrong.
7x^2-2x-7x+2=0
7x^2-9x+2=0
Use quadratic equation to solve

4) 6x^2-x-2=0
Use quadratic equation

Answer 5

No, you're not. You need to learn how the distributive property works and how to factor before you can learn how to solve with factoring.