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2007-06-07 06:00:40 · 6 answers · asked by kchief10 1 in Science & Mathematics Mathematics

6 answers

-5x -20 > 3x - 12
-20+12 > 3x +5x
-8 > 8x
-1 > x
x<-1

2007-06-07 06:08:03 · answer #1 · answered by Anonymous · 0 0

-5(x+4)>3(x-4)

Here are steps to simplify and solve any such inequality.
(1) multiply out terms

-5X -20 > 3X -12

(2) combine like terms, putting Xs on one side and constants
on the other by adding additive inverses
-5X -20 +20-3x > 3X-3X -12 +20 which becomes
-5x-3x > -12 +20 which becomes
-8x > 8
(3) Now by multiplying each side by the multiplicative inverse
and remembering since it is an inequality that if we
multiply by a negative number it changes the inequality
sign we get
(-1/8)(-8) x < (-1/8)(8) which becomes
x < -1

note 1: If when multiplying you multiply by a positive number it
leaves inequality sign the same.

Note 2. Had we moved the x terms and the constants to the other side we would have gotten (step 2):

-20 +12 > 3x +5x and thus -8 > 8x and thus (no need to change the inequality sign because multiplying by (1/8) a positive number we get -1 >x which read from right to left
still says x>-1

2007-06-07 06:22:13 · answer #2 · answered by ? 3 · 0 0

-5(x+4) > 3(x-4)
-5x - 20 > 3x - 12
-8x > 8
-x > - 8/8
-x > -1

2007-06-07 06:17:23 · answer #3 · answered by SSK 1 · 0 0

-5x -20 > 3x -12
-8>8x
-1>x or x<-1

2007-06-07 06:06:26 · answer #4 · answered by rick c 2 · 0 0

- 5x - 20 > 3x - 12
- 8 > 8x
x < - 1

2007-06-07 10:51:48 · answer #5 · answered by Como 7 · 0 0

-5x-20>3x-12

20>-2x-12

8>2x

4>x or x<4

2007-06-07 06:10:06 · answer #6 · answered by Anonymous · 0 0

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