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9 answers

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2007-06-07 03:48:55 · answer #1 · answered by ilovetosing. 3 · 1 0

7x - 5y = 12 can be written as 5y = 7x + 12 or y = 7x/5 + 12/7 and thus the slope is 7/5

10x + 14y = 2 can be written as 14y = -10x + 2

y = -10x/14 + 2/14 = -5x/7 + 1/7

The slope is -5/7

Since these two multiplied give -1, they are perpendicular. (tan a and tan 90+a are x and -1/x)

2007-06-07 04:21:15 · answer #2 · answered by Swamy 7 · 1 0

If they are perpendicular, then their slopes are the negative inverse of each other. So change them to y = mx + b format.

7x - 5y = 12
5y = 7x - 12
y = 7x/5 - 12/5 slope is 7/5

10x + 14y = 2
14y = -10x + 2
y = -10x/14 + 2/14
y = -5x/7 + 1/7 slope is -5/7

7/5 and -5/7 are negative inverses of each other, so these lines are perpendicular.

2007-06-07 03:52:12 · answer #3 · answered by TychaBrahe 7 · 1 0

Perpendicular lines have slopes that are negative inverses of one another...

7x - 5y = 12
y = (7/5)x - (12/5)

10x + 14y = 2
y = (-5/7)x + (1/7)

7/5 is the negative reciprocal of -5/7

Therefore the lines ARE perpendicular

2007-06-07 03:51:35 · answer #4 · answered by mark r 4 · 1 0

You need to know the slope so put them in point slope form:
y = mx + b where m is the slope.

14y = -10x + 2
y = -5/7x + 1/7

and

-5y = -7x + 12
y = 7/5x - 12/5

the slopes are -5/7 and 7/5 so they are perpendicular because they are opposite reciprocals.

2007-06-07 03:51:01 · answer #5 · answered by Justin M 4 · 1 0

true. Just change the form of the equations to slope-intercept form.

You have
y = (7/5)x - (12/5)
y = (-5/7)x + (1/7)

Lines are perpendicular when they are opposite repcipricals.
Like 2x and -(1/2)x

2007-06-07 03:50:28 · answer #6 · answered by iml 1 · 1 0

true!!! -5/7 is the exact opposite of 7/5

2007-06-07 03:50:14 · answer #7 · answered by Anonymous · 1 0

if their slopes equal to -1 when multiplied, they are perpendicular. therefore, the answer is true.

2007-06-07 03:50:57 · answer #8 · answered by Anonymous · 1 0

true

2007-06-07 03:50:29 · answer #9 · answered by Daisy 2 · 1 0

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