help thanks
2007-06-07 03:45:02 · 7 answers · asked by go play in the road 1 in Science & Mathematics ➔ Mathematics
1680 is their least common multiple; it's the smallest number that has them all as factors. You find this by first listing the prime factorizations of all the numbers.
16 = 2 x 2 x 2 x 2
20 = 2 x 2 x 5
24 = 2 x 2 x 2 x 3
28 = 2 x 2 x 7
Then you select the largest grouping of each prime factor. That's four 2's from 16, the 5 from 10, the 3 from 24, and the 7 from 28. You multiply those largest groups together to get 2 x 2 x 2 x 2 x 5 x 3 x 7 = 1680. Any multiple of 1680 also has all of the original numbers as factors, and they are the only numbers that do.
2007-06-07 03:48:16 · answer #1 · answered by DavidK93 7 · 1⤊ 0⤋
4
2007-06-07 03:52:20 · answer #2 · answered by Done 6 · 0⤊ 2⤋
4
2007-06-07 03:47:42 · answer #3 · answered by ch@L@nt 1 · 0⤊ 3⤋
2 and 4
2007-06-07 03:47:55 · answer #4 · answered by topsyk 3 · 0⤊ 3⤋
Multiply them all together, they will be factors of the result.
If you want the SMALLEST number that they are factors of, it is 3*4*4*5*7 = 1680
2007-06-07 03:52:11 · answer #5 · answered by morningfoxnorth 6 · 0⤊ 1⤋
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2016-05-18 23:49:29 · answer #6 · answered by cecilia 3 · 0⤊ 0⤋
1680 and all of its multiples.
2007-06-07 03:49:20 · answer #7 · answered by Anonymous · 1⤊ 0⤋