please i need help on this quiestion (4z + 7)(6z + 7)
2007-06-07 03:38:37 · 8 answers · asked by Is 2 in Science & Mathematics ➔ Mathematics
24z^2 + 70z + 49
I'd recommend the FOIL method. FOIL stands for First, Last, Inner, Outer, the pairs of terms that must be multiplied and then summed.
First: 4z*6z = 24z^2
Outer: 4z*7 = 28z
Inner: 7*6z = 42z
Last: 7*7 = 49
Sum: 24z^2 + 28z + 42z + 49 = 24z^2 + 70z + 49
2007-06-07 03:40:33 · answer #1 · answered by DavidK93 7 · 0⤊ 0⤋
Use the FOIL method (First, Outer, Inner, Last) to multiply each term together:
First terms: 4z * 6z = 24z^2
Outer terms: 4z * 7 = 28z
Inner terms: 7 * 6z = 42z
Last terms: 7 * 7 = 49
Placing these terms together in an equation, we get
24z^2 + 28z + 42z + 49
And combining the like terms, we end up with
24z^2 + 70z + 49
2007-06-07 10:43:35 · answer #2 · answered by mattside_bic 2 · 0⤊ 0⤋
(4z + 7) (6z + 7) = 24z^2 + 28z + 42z + 49 = 24z^2 + 70z + 49
2007-06-07 10:42:59 · answer #3 · answered by Swamy 7 · 0⤊ 0⤋
First, we take "4z" and multiply it with "6z", result is 24z^2.
Now, multiply "4z" with "+7", result is 28z.
Now take "+7" and multiply with "6z", result is 42z.
Multiply, "+7" with "+7", result is 49
Now sum it all up: 24z^2 + 70z + 49
2007-06-07 10:49:29 · answer #4 · answered by Ankthepot 1 · 0⤊ 0⤋
24z^2+70z+49
2007-06-07 10:41:50 · answer #5 · answered by MathGuy 6 · 0⤊ 0⤋
24z + 49
2007-06-07 11:05:22 · answer #6 · answered by Anonymous · 0⤊ 0⤋
24z^2+28z+42z+49
24z^2+70z+49
2007-06-07 10:44:03 · answer #7 · answered by Raziel Lives 4 · 0⤊ 0⤋
24Z^2+28Z+42Z+49
=24Z^2+70Z+49
OK?
2007-06-07 10:45:08 · answer #8 · answered by annan 2 · 0⤊ 0⤋