The answer is a.
3(x) + 2(y) = 5
3(5) + 2(-5) = 5
15 + (-10) = 5
15 - 10 = 5
5 = 5
2007-06-06 19:40:10
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answer #1
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answered by Megan 2
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Even if you wasnt given options to chooce from, you could solve the equation similar to how you would solve any equation.
if 3x + 2y = 5
then
2y = 5 - 3x
which means :
y = 2.5 - 1.5 x
so any answer can easily be checked by placing the value into x and there will be just the one value of y that will make the equation true.
try a) by putting 5 into x to give :
y = 2.5 - (1.5 x 5)
y = 2.5 - 7.5
y = -5
so if x is 5 y is -5 therefore a) is a solution,
you can try doing the same for b c and d but you will find that none of them are solutions to the equation
y = 2.5 - 1.5 x
so only a) is the correct answer there. Note that you should check all the answers as the equation can have many solutions, for example x = 3, y = -2 would be another solution
which would work.
2007-06-07 01:58:45
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answer #2
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answered by MARTIN B 4
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it's (a) undoubtedly!!
3(x) + 2(y) = 5
3(5) + 2(-5) = 5
15 + -10 = 5
15 - 10 = 5
5 = 5
2007-06-06 20:11:20
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answer #3
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answered by Anonymous
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3x +2y=5
by substitute a answer,
3x+2y
=3(5)+2(-5)
=15-10
=5#
by substitute b answer,
3x+2y
=3(-5)+2(5)
=-15+10
=-5----not equal to 5
by substitute c answer,
3x+2y
=3(-5)+2(6)
=-15+12
=-3----not equal to 5
by substitute d answer,
3x+2y
=3(6)+2(-5)
=18-10
=8----not equal to 5
so the answer a.
2007-06-06 19:44:46
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answer #4
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answered by jackleynpoll 3
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3 x 5 + (2 x -5) = 15 - 10 = 5
ANSWER a.
2007-06-06 19:42:33
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answer #5
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answered by Como 7
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yeah, it is a: 5, -5.
Just substitute the ordered pairs one by one into the equation 3x + 2y=5.
first number is x, second is y. order pair: (x, y)
(5, -5) is the only pair that works.
x= 5
y= -5
3x+2y=5
3(5)+2(-5)=5
2007-06-06 19:41:57
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answer #6
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answered by Diane S 2
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correct answer:a
put the values of x and y in the equation and you get your answer.
3(5)+2(-5)=5
15+(-10)=5
15-10=5
anyways in which grade are you in right now?
2007-06-06 19:43:58
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answer #7
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answered by Anonymous
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a.
(3*5)+(2*-5)=15+(-10)=15-10=5
2007-06-06 22:55:55
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answer #8
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answered by moon r 2
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the answer is a) you just hae to make the substitution in the quation and both sides must be equal
2007-06-06 19:40:07
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answer #9
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answered by Víctor V. 2
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a
2007-06-06 19:38:05
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answer #10
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answered by Anonymous
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