How would you solve this........???

Question

A wire measures 84 centimeters in length. It is cut into two pieces. The shorter piece is 6 centimeters shorter than the long piece. Find the length of each piece.

How would you solve this??

Answer 1

Call x the length of the shorter piece.
Since 84 cm is the total length, we can then call the length of the longer piece (84-x).

If x is 6 cm shorter than (84-x), then the equation looks like this:

x + 6 = 84-x
add x to both sides, sub 6 from both sides:
2x = 78
The shorter piece is 39 inches, the longer piece is 45 inches.
To check your work
39 + 45 = 84.

Hope that helps!

Answer 2

Very simple,see:

Let 'x' be the shorter piece length, and if u say that 'x' is shorter six times than long piece,it sounds that longer piece is 6 times long as shorter piece ( which is 'x' ), so:

x + 6x = 84
where,
x = shorter piece length
6x = longer piece length
since,we cut wire into two diffrent sizes,so
(shorter piece length ) + ( longer piece length ) = total length

so, 7x = 84
x = 84/7
x= 12 , this is the shorter piece length
since, longer piece length = 6x = 6 ( 12 ) = 72
so, that is answer.rite???

Answer 3

You would first divide 84 by 2 and get 42 cm for each piece. Then add 3 to one of the 42s and subtract 3 from the other so that they still add up to 84 but one length is 6 cms longer than the other piece. Giving you 39 cm and 45 cm.

Answer 4

Since we have two pieces both of which add up to 84 cm, we can write an equation to model the problem.

One piece is 6 cm longer than the other. Let's call the shorter piece x. That means the longer piece is x + 6. They must both add up to 84.

Therefore:

x + (x + 6) = 84

2x + 6 = 84
2x = 78
x = 39

Since x is the shorter piece, the shorter piece is 39 cm. ince the longer piece is 6 cm longer than the shorter piece, the longer piece is 45 cm.

Shorter piece = 39 cm
Longer piece = 45 cm

Answer 5

Algebra. L+S = 84. S = L-6. This solves easily to L = 45 and S = 39.

Answer 6

divide 84 in half. Add 3 to one half and take 3 from the other half. 42 plus 3 is 45, 42 minus 3 is 39. The length of each piece is 45 and 39.

Answer 7

Let the sides be x and x + 6

x + x + 6 = 84
2x + 6 = 84
2x = 78
x = 39
x + 6 = 45

The pieces are 39cm and 45 cm in length

Answer 8

1st wire (shorter piece), x;
2nd wire, y (longer piece).

x + y = 84 -- (A)

x = y - 6----- (B)

Substitute (B) into (A),
(y - 6) + y = 84
2y = 84 + 6 = 90
y = 90/2 = 45cm

x = 45 - 6 = 39cm

Answer 9

let two pieces be l and 84-l
now assume 84-l to be bigger
according o q
(84-l)-l=6
2l=78
l=39

Answer 10

x+(x-6)