math problem. help is appreciated. Thank You?

Question

the question is as follows(Jay flew his airplane 500 km against the wind in the same time that it took him to fly it 600 km with the wind. The speed of the wind was 20 km/h. What was the average speed of the airplane? The question is about rational expressions. Thank You

Answer 1

Suppose his speed is v km/h and it took him time t to fly each of the two distances.
Flying with the wind, his total speed was v+20 so we have t(v+20) = 600; flying against the wind his net speed was v-20 so we have t(v-20) = 500.

tv + 20t = 600
tv - 20t = 500
Combining these we get 40t = 100 and so t = 2.5 hours; and tv = 550, so v = 550/2.5 = 220.
So the speed of the plane was 220 km/h.

Answer 2

depends only an extra 300 or a cessna could fly at that speed was he diving or making barrell rolls during the flight

OMG maybe its an B52 stalling at 50 000 feet loosing altitude due to pressure problems inside the cabin Its all because of the damned apes

DAMN U APE MO FOs

Answer 3

P(t)=(Po)e^-kt Po = 50 P(t) = 10 t = 24 10 = 50e^(-ok(24)) a million/5 = e^(-ok(24)) (Divided the two sides via 50) ln(a million/5) = ln(e^-ok(24)) (organic logged the two sides) ln(a million/5) = (-ok(24))ln(e) (introduced down the exponent of a log. that's between the log residences) ln(a million/5) = (-ok(24)) (The ln(e) = a million. yet another log property) ok = (ln(a million/5))/-24 (divided the two sides via -24) ok = .067 P(4) = 50e^(-.067*4) = 38.24 instruments After 4 hours the tire nonetheless has extra advantageous than 0.5 the stress so i could say that's secure to force

Answer 4

580

Answer 5

i think 120mph