Write 1,386 as the product of its prime factors.
A. 2 x 693
B. 2 x 3 x 231
C. 2 x 3 x 7 x 33
D. 2 x 3 x 3 x 7 x 11
Please help me out. Thank you.
2007-06-06 15:49:36 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Let's do it as follows:
1386/2 = 693
693/3 = 231
231/3 = 77
77 = 7*11
The answer is D. 2*3*3*7*11.
2007-06-06 15:55:07 · answer #1 · answered by steiner1745 7 · 2⤊ 0⤋
= 2 x 693
= 2 x 3 x 231
= 2 x 3 x 3 x 77
= 2 x 3 x 3 x 7 x 11
ANSWER D
2007-06-07 02:50:15 · answer #2 · answered by Como 7 · 0⤊ 0⤋
It would be D because 1386 divided by 2 is 693 which can be divided by 3 to get 231 which can also be divided by 7 to get 33, divided by 3 to get 11. So 2 times 3 times 3 times 7 times 11 is 1386
2007-06-06 22:55:16 · answer #3 · answered by fencingfanatic13 2 · 0⤊ 0⤋
Note that 3 divides 693, 231 and 33, so the first 3 answers are not prime factorizations. So it must be D.
2007-06-06 23:14:40 · answer #4 · answered by doctor risk 3 · 0⤊ 0⤋
1386 = 2 * 693
= 2 * 3 * 231
= 2 * 3 * 3 * 77
= 2 * 3 * 3 * 7 * 11
The answer is (D)
2007-06-06 23:36:46 · answer #5 · answered by Akilesh - Internet Undertaker 7 · 0⤊ 0⤋