2^(6-x)=8^(x-2)
She needs the first step, I need the whole problem. Thanx bundlez!!
2007-06-06 14:40:02 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
8 = 2^3
2^(6 - x) = (2^3)^(x-2)
when you multiply a number that has a same base, you add the exponents
2^(6 - x) = 2^(3x - 6)
since both have the same base, the exponents have to be equal
6 - x = 3x - 6
12 - x = 3x
12 = 4x
x= 3
2007-06-06 14:44:02 · answer #1 · answered by 7 · 1⤊ 0⤋
as 8 = 2^3
2^(6-x)=2^[3(x-2)] so
6-x=3x-6 => 4x=12 and x=3
2007-06-06 14:47:29 · answer #2 · answered by santmann2002 7 · 1⤊ 0⤋
2^(6-x) = 2^3(x-2)
6 - x = 3x - 6
12 = 4x
x = 3
2007-06-06 14:42:48 · answer #3 · answered by Anonymous · 1⤊ 0⤋
it incredibly is not pre-calculus . feels like the predator-prey gadget and hence is a coupled gadget of differential equations. as a results of that we won't be able to easily verify a sort of purposes and then the different yet the two DEs must be solved concurrently. i could presume there is added element in a-c to establish the gadget.
2016-12-12 13:43:44 · answer #4 · answered by Anonymous · 0⤊ 0⤋