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I am hooking a rain barrel (50 gal plastic drum) to a soaker hose for the garden. I assume that the water pressure at the end of the hose will decrease proprtionally to the volume in the barrel. Correct, or does the spigot keep the pressure constant?

Assuming that pressure decreases, and that I want it to remain constant, and also assuming that the pressure from a 5 gal bucket is sufficient, would feeding the bucket from the barrel via a direct connection multiply the pressure coming out of the bucket, or would the press. remain the same as the bucket alone?

Would it matter if the connection went from barrel bottom to bucket top or bucket bottom? O-o_ O_o_ (O=barrel, o=bucket, -_= water lines) Barrel will be 3' off the ground, so bucket can be below barrel or even with it.

Both containers will be vented.

If not enough info, ask what you need to know.

2007-06-06 14:01:53 · 3 answers · asked by Anonymous in Science & Mathematics Physics

3 answers

The pressure on the water coming out of your hose is dependent on the height of the barrel and not the volume of the water in the barrel.

It's been a long time since I learned this and I don't remember the formula, but the height is the determining factor and not the volume.

2007-06-06 14:08:04 · answer #1 · answered by Joan H 6 · 0 0

The only thing that matters at all is the height from the bottom of the soaker hose to the top of the water in the barrel. Nothing else matters at all. The pressure at the soaker hose is proportional to its depth alone. If you want the pressure to remain constant, keep it at a constant depth below the water level of the barrel.

2007-06-06 21:13:52 · answer #2 · answered by ZikZak 6 · 0 0

http://www.abundantearth.com/store/rainbarrelkits.html

2007-06-06 23:41:46 · answer #3 · answered by Anonymous · 0 0

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