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a. Is the bond type between a phosphorus atom and a fluorine atom ionic, polar or nonpolar covalent? What calculations allowed you to derive at this?

b. Write the Lewis Dot Formula for the molecule formed from these two elements.

c. What is hte shape of the molecule?

d. Is this molecule asymmetrical or symmetrical in shape?

e. Is the molecule polar of nonpolar overall? Explain reasoning in terms of VSEPR Theory

2007-06-06 11:17:14 · 3 answers · asked by San Fran Kid 2 in Science & Mathematics Chemistry

3 answers

question a
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the bond is polar. the calculation is to determine the electronegativity difference between P and F. P has an electronegativity of 2.1. F has an electronegativity of 4. so their electronegativity difference is 1.9. since the difference is greater than zero but less than 2, the bond is polar covalent.

question b
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the molecule formed between P and F is called phosphorus trifluoride. the link below will take you to a page that shows a picutur of this molecule. the only addition you'll want to make to the picuture is to put 6 nonbonding electrons around each F. this will convert the pic into a lewis dot formula.

http://en.wikipedia.org/wiki/Phosphorus_trifluoride

quesiton c
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the shape of hte molecule is "trigonal pyramidal"

question d
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asymmetric

question e
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its polar overall. the single nonbonding pair of electrons on the P atom repels the bonding electrons more strongly than the bonding electrons repel each other. this forces the molecule into an asymmetric geometry, causing the molecule to be polar.

2007-06-06 13:37:24 · answer #1 · answered by Anonymous · 1 0

a) polar covalent

b) PF3 or PF5

c) Trigonal planar and Trigonal Bipyramidal

d) Both are symmetrical

e) Non polar.

2007-06-07 05:43:08 · answer #2 · answered by ag_iitkgp 7 · 0 0

The GMW of hydogen is 1 so that means that there is 29 g of Cl in the given amount of HCl. You notice that half of the Cl is used in MnCl2 so, therefore, half of the Cl is in the gas Cl2. Your answer is d) 14.6g.

2016-05-18 06:09:47 · answer #3 · answered by ? 3 · 0 0

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