Solve the inequality 4<2n+1<13??

Answer 1

So we have this equation: 4<2n+1<13.

The best thing to do is to split it to two parts, since we have e.g., from style a
Hence... Part One:
...............................

4 < 2n + 1
2n > 4 - 1
2n > 3

Therefore: n > 3/2 [or] n > 1.5


PART TWO:
....................
2n + 1 < 13
2n > 13 - 1
2n > 12

Therefore: n > 12/2 [or] n > 6

CONCLUSION: n is either ">1.5" or ">6".

Answer 2

First thing to remember is this inequality is an AND statement so:
4<2n+1 and 2n+1<13

Solve each inequality as if it were an equation:
4-1<2n which is 3<2n which becomes 3<2n

The first solution is 3/2
Next solve for 2n+1<13
2n<13-1 which is the same as 2n<12

The second solution answer is n<6

The FINAL ANSWER could be:
3/2 OR
3/2

Answer 3

Surely n can be either 2 3 4 or 5

when n=2
2n + 1 = 5 (which is greater than 4, but less than 13 )

same for when n = 3 4 or 5.

Answer 4

4 < 2n+1 < 13
4-1 < 2n < 13-1
3 < 2n < 12
3/2 < n < 12/2
1.5 < n < 6

Answer 5

Basically this is two inequalities jointed together.
One says 4<2n+1
And the other says 2n+1<13
But n must satisfy both.
When trying to solve, do one side at a time.
4<2n+1
3<2n (subtract 1 from both sides)
1.5
2n+1<13
2n<12 (subtract 1 from both sides)
n<6 (divide both sides by 2)

So now you know 1.5

Answer 6

3/2

Answer 7

3/2

Answer 8

4<2n+1<13
4-1<2n+1<13-1
3<2n<12
3/2<2n/2<12/2
3/2

Answer 9

26

Answer 10

Solve for each possible value of n

therefore n = 2,3.4 or 5