2007-06-06 10:56:25 · 4 answers · asked by candice t 1 in Science & Mathematics ➔ Mathematics
supposing that you meant
x^2=4y we´ll intercept both
so x^2/4=mx-9
x^2-4mx+36=0
This equation must have a double root ,to be the line tangent
so
16m^2-144= 0
so m=+-3
2007-06-06 15:38:05 · answer #1 · answered by santmann2002 7 · 0⤊ 0⤋
HELP! as written the problem is incomplete. By adjacent, do you mean tangent? Without knowing the degree of the equation, we can't give you a complete answer. So your question has two pieces of information missing to properly answer your question.
For instance, if the curve is defined as x^3 = 4y ( or x^5 or x^7), then there can be one value for m. If the equation is x^2 = 4y ( or x^4 or x^6), then there is more than one value for m. for degree 3, (x^3)/4 = mx-9 or (x^3)/4 - mx + 9 = 0. However, if x^z = 4 y, where the degree of the equation is z, the curve will always pass through the origin, either as a parabola (even degree) or ranging from the 3rd quadrant (negative values) into the first quadrant (positive values). Since the line intercepts the y axis where x = -9, and crosses the x axis at 9/m.
2007-06-12 11:30:31 · answer #2 · answered by steve s 3 · 1⤊ 0⤋
M is the value of the slope of the line tangent to the curve .
Use the slope formula to solve it
2007-06-12 13:44:02 · answer #3 · answered by Anonymous · 0⤊ 0⤋
did you mean x^4=y for the curve?
2007-06-06 18:01:34 · answer #4 · answered by Stop Sine 3 · 0⤊ 0⤋