y=x^2 is a simple graph; a parabola in the 1st and 4th quadrants. The unkown (a) will simply shift the parabola to the left or right of 0. Define a and your set.
2007-06-06 10:53:41
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answer #1
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answered by timdoas 3
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To draw this graph you have to know the shape of y=x^2 - it is a curved u shaped graph that is symmetrical about the y (vertical) axis.
The graph of x^2 goes through the origin (0,0) but the +a on the end of your graph means that the graph moves up a units so it will cross the y axis at 'a'.
2007-06-06 17:53:44
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answer #2
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answered by Anonymous
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First, let's ignore the "a" term and look at y = x^2.
When x = -2, y = 4
When x = -1, y = 1
When x = 0, y = 0
When x = 1, y = 1
When x = 2, y = 4
So what happens when y = x^2 + a?
Basically, the whole graph moves up by "a".
When x = -2, y = 4 + a
When x = -1, y = 1 + a
When x = 0, y = 0 + a
When x = 1, y = 1 + a
When x = 2, y = 4 + a
Hope that clarifies things to your satisfaction!
2007-06-06 17:52:52
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answer #3
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answered by Bramblyspam 7
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the graph of y= x^2 + a is a family of parabolas the +a will either raise or lower the parabola along the y-axis by exactly that value. so if a = -2 then the parabola intercepts the y-axis at (0,-2)
2007-06-06 17:54:19
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answer #4
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answered by z32486 3
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Graph y = x^2 first, and then move the graph vertically by "a" units.
2007-06-06 17:52:39
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answer #5
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answered by sahsjing 7
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It is a parabola that intersects the y-axis at a.
2007-06-06 17:50:12
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answer #6
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answered by grandemocha_sunchaser 2
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I dont im not in school anymore
2007-06-06 17:49:42
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answer #7
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answered by Anonymous
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uhh wat??!?!?! loll
2007-06-06 17:50:54
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answer #8
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answered by Anonymous
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