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2007-06-06 10:47:47 · 8 answers · asked by Anonymous in Science & Mathematics Mathematics

8 answers

y=x^2 is a simple graph; a parabola in the 1st and 4th quadrants. The unkown (a) will simply shift the parabola to the left or right of 0. Define a and your set.

2007-06-06 10:53:41 · answer #1 · answered by timdoas 3 · 0 1

To draw this graph you have to know the shape of y=x^2 - it is a curved u shaped graph that is symmetrical about the y (vertical) axis.

The graph of x^2 goes through the origin (0,0) but the +a on the end of your graph means that the graph moves up a units so it will cross the y axis at 'a'.

2007-06-06 17:53:44 · answer #2 · answered by Anonymous · 0 0

First, let's ignore the "a" term and look at y = x^2.

When x = -2, y = 4
When x = -1, y = 1
When x = 0, y = 0
When x = 1, y = 1
When x = 2, y = 4

So what happens when y = x^2 + a?
Basically, the whole graph moves up by "a".

When x = -2, y = 4 + a
When x = -1, y = 1 + a
When x = 0, y = 0 + a
When x = 1, y = 1 + a
When x = 2, y = 4 + a

Hope that clarifies things to your satisfaction!

2007-06-06 17:52:52 · answer #3 · answered by Bramblyspam 7 · 2 0

the graph of y= x^2 + a is a family of parabolas the +a will either raise or lower the parabola along the y-axis by exactly that value. so if a = -2 then the parabola intercepts the y-axis at (0,-2)

2007-06-06 17:54:19 · answer #4 · answered by z32486 3 · 1 0

Graph y = x^2 first, and then move the graph vertically by "a" units.

2007-06-06 17:52:39 · answer #5 · answered by sahsjing 7 · 1 0

It is a parabola that intersects the y-axis at a.

2007-06-06 17:50:12 · answer #6 · answered by grandemocha_sunchaser 2 · 3 0

I dont im not in school anymore

2007-06-06 17:49:42 · answer #7 · answered by Anonymous · 0 5

uhh wat??!?!?! loll

2007-06-06 17:50:54 · answer #8 · answered by Anonymous · 0 1

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