I need help with my math homework Please HELP!!!!!!!?

Question

In right triangle ACB,<(a line in the sign)C is the right angle.If Tan A = 4/3.then Cos B is equal to what???

Answer 1

Draw the picture of a right triangle with C as the right angle.

Tan A
= (opposite) / (adjacent)
= (segment BC) / (segment AC)
= 4/3

so
BC = 4
AC = 3

Using pythagorean theorem, you can find AB (the hypotenuse).

(AB)^2 = 4^2 + 3^2
(AB)^2 = 16 + 9
(AB)^2 = 25
AB = 5

Cos B
= (adjacent) / (hypotenuse)
= (segment BC) / (segment AB)
= 4 / 5

Answer 2

Start by drawing a diagram of the triangle ACB.

By definition, tan = opposite/adjacent.
Since tan A = 4/3, write in 4 as the length of BC and 3 as the length of AC.

You can then use Pythagoras to figure out the hypotenuse: It's the square root of (3^2 + 4^2) = sqrt(9+16) = sqrt(25) = 5.
Write in 5 as the length of AB.

By definition, cosine is adjacent/hypotenuse.
So cos B is 4/5.

Hope that helps!

Answer 3

4/5