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I am doing a review for my final and the book does not explain how to answer this problem.
EX:
Molarity=.024 (mol/L) of KOH
Liters= .064 L

2007-06-06 10:01:05 · 3 answers · asked by isthatmatt 4 in Science & Mathematics Chemistry

3 answers

KOH M= 56.106 g/mole

0.024 moles/liter = (0.024 moles*56.106g/mole)/L

= 1.3465 g/L

1.3465g/L * 0.064 L = 0.086 g

2007-06-06 10:08:18 · answer #1 · answered by Dr Dave P 7 · 0 0

First multiply molarity and volume to obtain the # of moles. Then multiply the # of moles by the molar mass of KOH (56.10564 g/mol).
so 0.024 * 0.064 = 0.001536 mol
and 0.001536 * 56.10564 = 0.086 g

2007-06-06 10:24:38 · answer #2 · answered by stuart b 2 · 0 0

Try volume x molarity x Mr

2007-06-06 10:08:43 · answer #3 · answered by Gervald F 7 · 0 0

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