Note first that |2x = 5| = |2x - (-5)|.
Next, think of the absolute value of a difference as a distance and the problem as being equivalent to:
find the values of x where the distance from 2x to (-5) is less than 13.
--> then (-5) -13 < 2x < (-5) +13
or
-18 < 2x < 8
or
-9 < x < 4.
So, the answer is 'none of these'.
2007-06-06 09:19:23
·
answer #1
·
answered by chancebeaube 3
·
1⤊
2⤋
1st take every thing out of absolute value bars.
So it will be
2x+5<13
Subtract 5 from both sides
2x+5<13
-5 -5
2x+0<8
Divide 2 by both sides
2x/2<8/2
x=4
So to fix the answer you minus 5 which is -5 and we know x is 4 and -5 is<4 and when we had subtracted 5 from 13 we got 8 and 4 is <8.
It should look like this
-5<4<8
2007-06-06 09:31:16
·
answer #2
·
answered by cardinal_lyfe 1
·
0⤊
1⤋
Hi,
| 2x + 5 | < 13
-13 < 2x + 5 < 13
- 18 < 2x < 8
-9 < x < 4
So none of the choices given in the problem are correct.
Good luck
2007-06-06 09:29:02
·
answer #3
·
answered by sudhakarbabu 3
·
0⤊
1⤋
Strictly speaking 2x + 5 < 13 => x < 4 besides the fact that it additionally has a cap at x > -9 => |2(-9) + 5| = 13 subsequently, -9 < x < 4 could desire to be your answer. via removing, a. via attempting 4, we get 13 < 13 which isn't genuine b. via attempting 7, we get 19 < 13, which isn't genuine c. comparable as b. d. it quite works yet no longer the full selection e. i could choose this. besides the fact that it relies upon if this could be a severe question or a trick question as d is likewise a available answer.
2016-11-26 20:12:46
·
answer #4
·
answered by ? 4
·
0⤊
0⤋
This inequality can be changed to
-13 < (2x+5) < 13
Now isolate x by subtracting 5 from all three places and dividing everything by 2
-18 < 2x < 8
-9 < x < 4
2007-06-06 09:21:21
·
answer #5
·
answered by Anonymous
·
2⤊
2⤋
it is none of these the correct answer is -9
the above qwes. means that 2x+5 can be less than 13 or greater than -13 now solving the two you can get the answer
-13<(2x+5)<13
adding -5 to each side
-18<2x<8
dividing each side by 2
-9
2007-06-06 09:24:32
·
answer #6
·
answered by Jimmy 2
·
1⤊
1⤋
| 2x + 5 | < 13
To solve this, note that an absolute inequality in the form
|z| < c (for positive constant c) equates to the following inequality:
-c < z < c
Same deal here.
|2x + 5| < 13
-13 < 2x + 5 < 13
Now, isolate x as per the usual methods. Subtract 5 to the inequality gives us
-18 < 2x < 8
Divide by 2,
-9 < x < 4
2007-06-06 09:22:13
·
answer #7
·
answered by Puggy 7
·
2⤊
2⤋
| 2x + 5 | < 13
solve positive
2x + 5 < 13
2x < 8
x < 4
and negative
2x + 5 > -13
2x > -18
x > -9
then put them together
-9 < x < 4
2007-06-06 09:35:35
·
answer #8
·
answered by rockbabe 2
·
0⤊
1⤋
If 2x+5>0 so x> -5/2
2x+5>13 snd x >4
If 2x+5<=0 so x<=-5/2
-2x-5<13 so 2x >-18 and x>-9
The solution is
-94
By error I solved I2x+5I>13 but the proceedings are the same
2007-06-06 09:24:27
·
answer #9
·
answered by santmann2002 7
·
1⤊
2⤋
With the "less than" sign, there is no definitive value for x.
The equation becomes 2x<8, then x<4; so x can be 1, 2 or 3.
2007-06-06 09:26:36
·
answer #10
·
answered by fedger@rogers.com 1
·
0⤊
1⤋