if Log6(t-1)=2, what is value of t ?

Answer 1

t = 53/3

I'm assuming the logarithm function is operating on the entire argument [6(t-1)].

Answer 2

Log6(t-1)=2
6(t-1) = 10^2
6t -6 = 100
6t = 100 + 6
6t = 106 divide by 6
t = 106 / 6 = 53/3 = 14 1/3

Answer 3

im guessing that 6 is the base so:

According to the Change of base theorem:

Log(t-1)
______ = 2
Log(6)

Multiplying log6 to both sides:

Log(t-1) = Log(36)

(i got 36 because 2Log6 is the same as Log6^2 or Log36)



Taking the Log inverse of both sides:

t - 1 = 36

Adding 1 to both sides therefore gives us:

t = 37






BEST ANSWER PLS :P

Answer 4

The log, base 6, of t - 1 equal 2

written in exponential form is

6^2 = t - 1

36 = t - 1

37 = t

Or, log, base 10, of 6(t - 1) = 2

written in exponential form is

10^2 = 6(t - 1)

100 = 6t - 6

106 = 6t

53 / 3 = t

Answer 5

If it is base 6, then
t-1 = 36
t = 37
---------
If it is base 10, then
t-1 = 100/6
t = 106/6 = 53/3 = 17 2/3

Answer 6

6^2=t-1
36=t-1
37=t

Answer 7

Let log be log base 6:_
log (t - 1) = 2
t - 1 = 6²
t - 1 = 36
t = 37

Answer 8

supposing Log means logs base6
(t-1)=6^2 so t-1=36 and t=37

Answer 9

(t-1) = 6^2
t=37