3x^2 + 11x + 4 = 0
using quadratic formula
a = 3, b = 11, c = 4
x = (-11 +- sqrt(121 - (4*3*4)))/(2*3)
x = (-11 +- sqrt(121 - 48))/6
x = (-11 +- sqrt(73))/6
x = (-11 +- 8.54)/6
x = -3.26 or -0.41
sum of solution = -3.26 - 0.41 = -3.67 = -3 2/3
2007-06-11 10:23:29
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answer #1
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answered by topsyk 3
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Sum of the Roots of a Quadratic Equation
If ax^2 + bx + c = 0,
then the sum of the roots is equal to -b / a.
If 3x^2 +11x + 4 =0,
then the sum of the roots is equal to -11 / 3 or -3 2/3.
2007-06-06 15:12:18
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answer #2
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answered by mathjoe 3
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3X(squared) + 11X + 4 = 3 XX + 11 X + 4
= 18 + (X-1) X
2007-06-14 05:47:20
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answer #3
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answered by Si semut 4
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There is a quick way to answer this question without deriving the zeros:
In any qudratirc, ax^2 + bx + c,
1) the sum of the roots = -b/a
and
2) the product of the roots = c/a.
So, your answer would be -(11/3).
This method can be expanded to other polynomials besides quadratics. For instance:
for the quartic ax^4 + bx^3 + cx^2 + dx +e,
1) the sum of the roots = -b/a
and
2) the product of the roots = e/a.
In a cubic (or any 'odd' power polynomial) the product will be the negative ratio of the leading coefficient to the constant.
2007-06-13 14:09:53
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answer #4
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answered by chancebeaube 3
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its possible if you have 3x^2+11x-4
3x^2+12x-x-4
(3x-1)(x+4)
x=1/3 or x = -4 (your solution)
sum of solutions
-4+(1/3)
-11/3 its the same as writing -3*(2/3)
2007-06-06 15:06:02
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answer #5
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answered by Anonymous
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the sum of the roots is eqaul to the - b term dived by the a term
in other words
sum= -11/3
formula's work wayy easier thean doing it all out if you know them :O)
so in the future just so you know the product=c/a
2007-06-06 15:12:23
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answer #6
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answered by lovabledai 2
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Let x1 and x2 be the two roots.
3x^2+11x+4 = 3(x-x1)(x-x2) = 3x^2-3(x1+x2)x+3x1x2
Compare the coefficients of x,
11 = -3(x1+x2)
x1+x2 = -11/3 = -3 2/3
2007-06-06 15:07:10
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answer #7
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answered by sahsjing 7
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-11/3
2007-06-06 18:00:53
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answer #8
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answered by UNIQUE 3
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this is clearly a quadratic equation.
the equation to retrieve the solution is provided on this website:http://id.mind.net/~zona/mmts/miscellaneousMath/quadraticRealSolver/quadraticRealSolver.html
since it is complex to type it out here i would suggest you visit this link.
by plugging in the values based on the equation the correct answer is close to -3 2/3
2007-06-06 15:09:23
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answer #9
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answered by kaddu747 2
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Use the quadratic formula or divide everything by 3 and try factoring. The quadratic would be easier, I think.
2007-06-06 15:08:31
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answer #10
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answered by Fa Q 2
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