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2007-06-06 07:45:25 · 12 answers · asked by Anonymous in Science & Mathematics Astronomy & Space

12 answers

Black holes - a sizable region, whose gravitational escape velocity exceeds that of light, caused by a huge mass contained within a point - move through space just as anything else, influenced by the gravitation of all other objects, or alternatively, influenced by the surrounding spacetime curvature.

Also, the mass itself has a spin preserved during its collapse which sped up due to the reduction in radius. The entire hole spins and there are ejections of matter at its poles fed by a portion of the matter being drawn in from its surroundings.

2007-06-09 07:43:40 · answer #1 · answered by ? 5 · 0 0

No, like everything else in the universe, they are (or should be) in constant motion. Unless you have plans to go and visit a black hole (in which case it would appear to get rapidly larger because of how you will be sucked in at a great velocity), it would appear stationary.

2007-06-06 15:03:13 · answer #2 · answered by Anonymous · 0 0

Nothing in the universe is stationary.

2007-06-06 21:51:58 · answer #3 · answered by Anonymous · 0 0

Nothing in the universe is stationary, everything is in free fall.

2007-06-10 18:47:35 · answer #4 · answered by johnandeileen2000 7 · 0 0

Nothing in this universe is stationary...

2007-06-06 15:00:13 · answer #5 · answered by BRB 2 · 0 0

no many of them spin rapidly . According to theoretical physics this may prevent total gravitational collapse to infinity
and potentially create worm holes .

2007-06-12 13:11:53 · answer #6 · answered by Anonymous · 0 0

No - most used to be stars so they're free to move about the universe.

2007-06-06 14:54:40 · answer #7 · answered by Gene 7 · 0 0

actually there supposedly in constant movement and always will be, because they are just collapsed stars.

2007-06-12 00:35:19 · answer #8 · answered by KEEVON!!! 2 · 0 0

Filthy beast

2007-06-06 15:04:38 · answer #9 · answered by Anonymous · 0 1

no

2007-06-11 15:01:28 · answer #10 · answered by Lexington 3 · 0 0

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