What is the balanced chemical equation for the combustion of 2-methyl-1-butene?

Question

What is the balanced chemical equation for the combustion of 2-methyl-1-butene?

a.C6H12(g) + 9 O2(g) → 6 CO2(g) + 6 H2O(λ)
b.C4H8(g) + 6 O2(g) → 4 CO2(g) + 4 H2O(λ)
c.2 C5H10(g) + 15 O2(g) → 10 CO2(g) + 10 H2O(λ)
d.2 C4H10(g) + 13 O2(g) → 8 CO2(g) + 10 H2O(λ)
e.C5H12(g) + 13 O2(g) → 5 CO2 (g) + 6 H2O(λ)

Answer 1

This is a trick question because all of the equations are balanced combution equations. You don't need to know how to balance an equation to do this one.
You need to know how many carbons and hydrogens would be in 2-methyl-1-butene. (Only 1 formula represents 2-methyl-1-butene). Butene has 4 carbons but you also have an additional methyl group so you know the correct answer can only be "c" or "e" (both have 5 carbons). A butene is a butane with a double bond, so it has 2 less carbons that a saturated hydrocarbon. A saturated hydrocarbon has a formula of C(n)H(2n+2) so a hydrocarbon with 1 double bond should have a formula of C(n)H(2n) so "c" is the correct answer.

Answer 2

c.2 C5H10(g) + 15 O2(g) → 10 CO2(g) + 10 H2O(λ)

Answer 3

That is impossible.