2007-06-06 06:52:00 · 12 answers · asked by Amy M 5 in Science & Mathematics ➔ Mathematics
3y+12-10=66-5y
3y+5y=66-12+10
8y=64
y=8
2007-06-06 06:55:06 · answer #1 · answered by sweet n simple 5 · 1⤊ 0⤋
:3(y+4)-10=66-5y
3y + 12 - 10 = 66 - 5y
3y + 2 = 66 - 5 y
3y + 5y = 66 - 2
8 y = 64 divide by 8
y = 8
2007-06-06 07:31:07 · answer #2 · answered by muhamed a 4 · 0⤊ 0⤋
Y=8
Multiply out the first equation : 3y +12-10=66-5y
Which is actually 3y + 2 = 66-5y
Subtract 2 from both sides : 3y = 64 - 5y
Now add 5y to each side : 8y = 64
Divide both sides by 8 leaving you with y = 8
2007-06-06 07:02:53 · answer #3 · answered by Anonymous · 0⤊ 0⤋
3(y+4) - 10 = 66 - 5y
3y + 12 - 10 = 66 - 5y
3y + 5y = -12 + 10 + 66
8y = 64
y = 64/8
y = 8
Hope I helped!
2007-06-06 08:13:47 · answer #4 · answered by Buttons 3 · 0⤊ 0⤋
3y + 12 - 10 = 66 - 5y
3y + 5y = 66 - 12 + 10
8y = 64
y = 8
2007-06-06 06:56:46 · answer #5 · answered by sassyndeej 3 · 1⤊ 0⤋
3(y+4)-10=66-5y
3y+12-10=66-5y (distribute the 3)
3y=64-5y (add 10 and subtract 12 from both sides)
8y=64 (add 5y to both sides)
y=8 (isolate the variable by dividing both sides by 8)
2007-06-06 07:03:10 · answer #6 · answered by kdlady 2 · 0⤊ 0⤋
8
2007-06-06 06:59:45 · answer #7 · answered by Think Y 2 · 0⤊ 0⤋
3y + 12 - 10 = 66 - 5y
8y = 64
y = 8
2007-06-06 08:30:46 · answer #8 · answered by Como 7 · 0⤊ 0⤋
3(y+4)-10=66-5y
3y+12-10=66-5y
3y - 3y = 0 -5y-3y= -8y
12-10 = 66-5y
-10+10=0 66+10=76
12=76-5y
12-(-76)= -64 76-(-76)=0
-64=-8y
-64/8=-8 -8y/8y=y
y= -8
2007-06-06 07:15:13 · answer #9 · answered by Anonymous · 0⤊ 0⤋
y=8
2007-06-06 06:55:27 · answer #10 · answered by xandyone 5 · 0⤊ 0⤋