Propene + Bromine [water] = ????
C(3)H(6) + Br(2) = ????
thanks
2007-06-06 06:37:00 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
C3H6 + Br2 => C3H6Br2
or
CH2=CH-CH3 + Br2 => CH2Br-CHBr-CH3
The bromines simply are added to the carbons where the double bonds were located. The product is 1,2-dibromopropane.
2007-06-06 06:43:29 · answer #1 · answered by hawkeye3772 4 · 1⤊ 0⤋
C3H6 + Br2 = C3H6Br2
Dibromopropane - the bromine will add to the propene across the double bond
2007-06-06 06:41:11 · answer #2 · answered by Showaddywaddy 5 · 1⤊ 0⤋
By bromine water, do you mean Br2 dissolved in water, or HBr? The latter is hydrogen bromide, but the reactions are similar:
propene + bromine = 1,2-dibromopropane
propene + hydrogen bromide = 1-bromopropane *and* 2-bromopropane
For the reaction with hydrogen bromide, you will get more 2-bromopropane than 1-bromopropane.
2007-06-07 00:20:40 · answer #3 · answered by Anonymous · 0⤊ 0⤋
C3H6 + Br2 -> C3H6Br2
1,2 - Di Bromo Propane.
2007-06-06 07:05:26 · answer #4 · answered by ag_iitkgp 7 · 1⤊ 0⤋
C3H6 + Br2 = C3H6Br2 [1,3-dibromopropane or trimethylene dibromide if you want the mouthful version!!]
2007-06-06 16:37:33 · answer #5 · answered by triptipper 3 · 0⤊ 0⤋
it's bromination....
C3H6+Br2=C3H6Br2....(dicolourization occurs showing that it's an unsaturated hydrocarbon)
2007-06-06 10:32:02 · answer #6 · answered by George 3 · 0⤊ 0⤋
gives CH2Br-CHBr-CH3 i think
balances itself
2007-06-06 09:36:06 · answer #7 · answered by coy carp 3 · 0⤊ 0⤋