2007-06-06 06:21:04 · 2 answers · asked by tyler a 1 in Science & Mathematics ➔ Chemistry
how many grams of NaNO2 are produced;
Which reactants are in excess and how many grams or each remain after the reaction.
2007-06-06 06:23:53 · update #1
4NO+O2+NaCO3 ---> 4NaNO + 2CO2
how many grams of NaNO2 are produced?
which reactants are in excess and how many grams of each remain after the reaction?
2007-06-06 06:55:17 · update #2
4NO+O2+NaCO3 ---> 4NaNO + 2CO2
154g Na2CO3 75g O2 and 105g NO
how many grams of NaNO2 are produced?
which reactants are in excess and how many grams of each remain after the reaction?
2007-06-06 06:56:42 · update #3
The balanced equation is :
4NO + O2 + 2 Na2CO3 >> 4 NaNO2 + 2CO2
About the other questions you have to tell me moles or grams of reactants and I can answer you
Well.
Moles Na2CO3 = 154 g / 106 = 1.45 ( 106 is the molecular weight of Na2CO3)
Moles O2 = 75 g / 32 = 2.34
Moles NO = 105 / 30 = 35
the ratio between NO , O2 and Na2CO3 is 4 : 1 : 2 so Na2CO3 is the limiting reactant.
the ratio between Na2CO3 and NaNO2 is 2 : 4
2 : 4 = 1.45 : x
x = 2.9 ( moles NaNO2 ; molecular weight = 69 g/mol)
2.9 mol x 69 g/mol = 185.6 g
2007-06-06 06:41:08 · answer #1 · answered by Dr.A 7 · 1⤊ 0⤋
4 NO + O2 + 2 Na2CO3 -> 4 NaNO2 + 2 CO2
2007-06-06 14:39:18 · answer #2 · answered by ag_iitkgp 7 · 0⤊ 0⤋