math help please?

Question

1. In many families both parents work, as a result there is increasing need for day care. Data was collected; and one year in Canada approximately 32% of children aged 0 to 11 years were in day care for at least 20h per week.
What is the probability, in a random poll of 60 children from the ages of 0 to 11 that more than 15 children are in day care at least 20h per week?
p(k)= nCk P^k (1-p)^n-k
were
n= 60
p=0.32
k= 15
q= 1-0.32= 0.68
so:
p(k) = 60C15 x 0.32^15 (0.68) ^60-15
= 0.0583464079
is this correct?

1b) What is the probability in a random poll of 60 children that fewer than 20 are in a day care at least 20h per week?

How would I do this because it says fewer?

Answer 1

In first question, you have calculated the probability that exactly 15 children are in care. To find the probability of more than 15, that is, a number from 16 to 60, you need to do that calculation for each number and add the results. In this case it would be easier to add for 0 through 15 and then subtract that result from 1. Either way should get the same answer.

For the second, proceed similarly. Add the results from 0 through 19. That is the answer.

Answer 2

i think its correct