2007-06-06 04:33:26 · 7 answers · asked by M.O. 1 in Science & Mathematics ➔ Mathematics
10/3. Just flip the fraction and invert the signs.
2007-06-06 04:36:23 · answer #1 · answered by jjsocrates 4 · 1⤊ 0⤋
strains that are perpendicular have opposite reciprical slopes. in different words, if line AB has slope -3/10, then a perpendicular line could have a slope +10/3. in case you're taking into consideration this, you will discover why that's real. strains that are parallel will by no capacity bypass, so they could have a similar slope. So if CD is parallel to AB, and the slope of AB is -5, the slope of CD is likewise -5.
2016-12-18 15:42:15 · answer #2 · answered by zagel 4 · 0⤊ 0⤋
The slopes of perpendicular lines are opposite reciprocals. First multiply the slope by -1:
-3/10(-1)
3/10
Now find the reciprocal of 3/10 by dividing 1 by 3/10:
1 ÷ 3/10
1 (10/3)
10/3
So, the slope of CD is 10/3.
***Another way is just to divide -1 by the slope.***
2007-06-06 04:49:54 · answer #3 · answered by wannalala 3 · 1⤊ 0⤋
Two non vertical lines are perpendicular if and only if their slopes m1 and m2 are such that m1*m2 = -1.
m1 = -1/m2
m1 = -1/(-3/10)
-1/(-3/10) = the negative inverse (flip the fraction & change the sign) of -3/10
m1 = -1/(-3/10) = 10/3 or 3 1/3 (This is your answer.)
2007-06-06 04:57:20 · answer #4 · answered by SusanB 5 · 0⤊ 0⤋
If gradient of Line 1 is m1 and gradient of perpendicular line L2 is m2 then:-
m1 x m2 = - 1
(- 3 / 10) x m2 = - 1
(3/10) x m2 = 1
m2 = 10/3
2007-06-06 08:28:34 · answer #5 · answered by Como 7 · 0⤊ 0⤋
10/3 the slopes of perpendicular lies are opposite reciprocals, which means the multiply to give negative one.
2007-06-06 04:42:47 · answer #6 · answered by mom 7 · 1⤊ 0⤋
Take negative of reciprocal:
+10/3.
2007-06-06 04:38:18 · answer #7 · answered by dutch_prof 4 · 1⤊ 0⤋