algebra two.....?

Question

19: Solves these applications with any method from our lessons.
In a right triangle, if c = 12 and b = 10, what is the length of a in simplified form?
4√11
2√11
22


20: In a right triangle, if a = 8 and c = 14, what is the length of b in simplified form?
2√33
4√33
11


21: In a right triangle, if a = and b = , what is the length of c in simplified form?
6
-12
12


22: The product of two consecutive integers is 380. Find the integers.
19 and 20
21 and 22
29 and 30


23: The height of a triangle is 5 m less than half its base. If the area of the triangle is 300 m2, find the measure of the height.
12 m
15 m
16 m


24: The length of a rectangle is 3 inches more than twice the width. The area is 27 square inches. What is the length?
9 in
11 in
12 in


25: The diagonal of a rectangle is 13 meters. The length is 2 meters more than twice the width. What is the length?
10
11
12

Answer 1

do your own homework or you'll never get ahead in life.

Answer 2

19) Hopefully they mean that c is the hypotenuse...
... c^2 = a^2 + b^2
... 144 = a^2 + 100
... a^2 = 44
... a = V44 = V(4 . 11) = 2 V11.

20)
... c^2 = a^2 + b^2
... 196 = 64 + b^2
... b^2 = 132
... b = V132 = V(4 . 33) = 2 V33.

21) ??

22) Don't know if they taught you this trick, but I choose n to be the average of the two numbers; then
... (n - 1/2) (n + 1/2) = 380
... n^2 - 1/4 = 380
... n^2 = 380 1/4 = 1521/4
... n = V(1521/4) = 39/2 = 19 1/2.
The numbers are 19 and 20.

23) Write 1/2 b = h + 5, then
... A = (1/2 b) h
... 300 = (h + 5) h
... h^2 + 5 h = 300
... (h + 2 1/2)^2 = 306 1/4 = 1225/4
... h + 2 1/2 = +-35/2 = +-17 1/2
... h = 17 1/2 - 2 1/2 = 15

24) L = 2W + 3
... A = L W
... 27 = (2W + 3) W
... 2W^2 + 3W - 27 = 0
... (2W + 9) (W - 3) = 0
... W = -4 1/2 [nonsense] or W = 3
... L = 2*3 + 3 = 9

25)
... D^2 = L^2 + W^2
... 169 = (2W + 2)^2 + W^2
... 169 = 5W^2 + 8W + 4
... 5W^2 + 8W - 165 = 0
... (5W + 33) (W - 5) = 0
... W = -33/5 [nonsense] or W = 5
... L = 2*W + 2 = 12.

Answer 3

This is an awful lot of work, but I can help you get started ...

19:
c = 12 and b = 10: find a.

We know that a² + b² = c²,
so a² + 10² = 12², and a² = 44

√44 = ... I'll let you simplify it from here.

20:
a = 8 and c = 14: find b.
again, a² + b² = c², so b² = 14² - 8²

Solve as shown in 19.

21:
Numbers aren't given, but you can proceed as in 19 and 2-.

22:
Two consecutive integers multiply to 380. So one integer is x, and the next consecutive integer is (x+1).

x*(x+1) = 380. Multiply out and use the quadratic formula to obtain your roots.

23:
Area of a triangle = (1/2)*b*h
The height can be rewritten as [b-(5/2)]

Area = (1/2)*b*(b-(5/2)) = 300

Multiply out and use the quadratic formula to obtain your roots.

24:
A = l * w, and the length can be rewritten as 2w+3

A = (2w+3)*w = 27

Multiply out and use the quadratic formula to obtain your roots.

25:
The diagonal divides the rectangle into two right triangles.

Rewrite the length and width in similar terms (you've already done it for the earlier problems), and use

a² + b² = c², where c is 13.

Good luck.

Answer 4

without knowing which angle is the rt angle i will assume....

19) a^2 = 12^2 - 10^2
= 144 -100
= 44
a = rt44
= rt(11.2^2)
= 2rt11

20) as above..... 196 -64 = 132 = rt (33.2^2) = 2rt33

21) nfi



22) xy =380 ; x-y=1 solve the equaitons
Answer 19 and 20

23) 300 = 1/2bh
h= 1/2b - 5
solve equations
Answer 12 (10 is negative and you cant have negative length)

24) 27 = lw
l = 2w +3
solve equaitons
Answer 9in (3/2in is negative - see above)

25) 13^2 = l^2 +w^2
l= 2w +2
Solve equations
Answer 12m (only positive answer)

Answer 5

If you're good at algebra, then you'll be good at algebra 2. It's not a horrible difference. Click on the website below, it gives a little explaination differenciating the 2

Answer 6

For the right triangle questions, which letter, a,b,or c is the diagonal part of the triangle?

#22 19 and 20
#24 the length is 9 in
#25 the length is 12

Answer 7

19.
a^2 + b^2 = c^2
a^2 + 10^2 = 12^2
a^2 + 100 = 144
a^2 = 44
a = 2 * sqrt(11)

22.
x * (x + 1) = 380
x^2 + x = 380
x^2 + x - 380 = 0
x = (-1 +/- sqrt(1 + 1520))/2
x = (-1 +/- sqrt(1521))/2
x = (-1 +/- 39)/2
x = -40/2 or x = 38/2
x = -20 or x = 19
19 and 20 are one answer
-19 and -20 also works.

23.
h = b/2 - 5
A = 1/2*hb = b/2 * (b/2 - 5)
b^2/4 - 5b/2 = 300
b^2 - 10b = 1200
b^2 - 10b - 1200 = 0
b = (10 +/- sqrt(100 + 4800))/2
b = (10 +/- sqrt(4900))/2
b = (10 +/- 70)/2
b = 80/2 or -60/2
b = 40 (obviously b can't be a negative number)

h = b/2 - 5
h = 40/2 - 5
h = 20 - 5
h = 15


24.
L = 2W + 3
L * W = 27
(2W + 3)W = 27
2W^2 + 3W = 27
2W^2 + 3W - 27 = 0
W = (-3 +/ sqrt(9 + 216))/2
W = (-3 +/ sqrt(225))/2
W = (-3 +/ 15)/2
W = 12/2 or -18/2
W = 6

L = 2W + 3
L = 12 + 3
L = 15

You should be able to solve the rest now.

Answer 8

19. 2 square root of 11
20. 2 square root of 33
21. you didn't type in what a and b equal, but the answer isn't -12
22. 19 and 20
23. 15 m
24. 9 in
25. 12 m

Answer 9

And how exactly have you helped tinket except in allowing this guy to become lazier and more dependent??

Answer 10

Do your own homework.