Algebra Two...?

Question

10: 3x^2 + 4x + 3 = 0

11: Solve by using the quadratic formula.
2x^2 + 4x = -1

12: x^2 + 2x + 3 = 0

13: -2x^2 + 3x + 3 = 0

14: 2x(x + 2) = 5

15: Use the discriminant to determine the nature of the roots:
x^2 = 13x - 36

Answer 1

Problem 10

Quadratic formula

x = - b ± √b² - 4ac / 2a

3x² + 4x + 3 = 0

a = 3

b = 4

c = 3

x = - 4 ± √(4)² - 4(3)3) / 2(3)

x = - 4 ± √16 - 36 / 6

x = - 4 ± √- 20 / 6

x = - 4 ± i √20 / 6

x = - 4 ± 4.472135955i / 6

- - - - - - - -

Solving for +

x = - 4 + 4.72135955i / 6

x = 0.472135955i / 6

x = 0.078689326i

- - - - - - - -

Solving for -

x = - 4 - 4.472135955i / 6

x = - 8.472135955i / 6

x = - 1.412022659i

- - - - - - - s-

Answer 2

HINT:solution of an equation
ax^2+bx+c=0,where a,b,c are constants and a=/=0 ;is given by

x=[ -b+/-{b^2-4ac}^(1/2)]/2a.

Answer 3

10) -2/3 + sqrt(5)/3 * i, -2/3 - sqrt(5)/3 * i

11)-1.7071, -.2929

12) -1 + sqrt(2) i, -1 - sqrt(2) i

13) -.6861, 2.186

14) -2.87, .87

Answer 4

So what's the problem?? Git 'er done!!

Doug