How much energy must be added to a 2-kg piece of aluminum with a specific heat of 900 J/(kgoC) to increase its

Question

temperature from 10oC to 50oC?


A. 1,800 J
B. 72,000 J
C. 108,000 J
D. 900,000 J

Answer 1

You just need to take the product of the mass, the specific heat, and the change in temperature, which is 40 degrees C, or 40 K.

(2 kg)(900 J/kg-K)(40 K) = 72,000 J

B) 72,000 J

Answer 2

David K is correct....

Energy Required = Mass x Specific Heat x Change in Temp
Energy Required = 2 x 900 x (50 - 10) = 72,000 Joules.

Answer 3

So we've been given a 10kg piece of aluminium. particular warmth tells you, how plenty enegery you do ought to warmth a million kilo of aliminium by a million degree. for that reason its going to be permit Q be the enegry m the mass c the particular warmth and t the temperature distinction Q = m * c * t Q = 10 kg * 900 j / kg C * 5 C Q = 40 5 000 J = 40 5 kJ

Answer 4

The answer is C , it's not nice to try and show off at the expense of others, you and I both know there are only a hand full of people who could even grasp the question you posed, okay, so now you are at play in the back yard of GOD's house, no need to rub others faces in the feed....

Take care....
P.S. we all remember the kid in the 3rd grade who asked the teacher a question he already knew the answer to , just so he could show the rest of us dummies he knew it, we never liked him .. please don't tell me that was you ? :)
Jk, thanks for the Question