9 can be obtained by 3 + 6, or 4+5.
The odds of a 3,4,5 or 6 on one die are each 1/6.
The same for the other die.
So the odds of 3 from one and 6 in the other are 1/36, 4 with 5 is 1/36 and 5 with 4 is 1/36 and 6 with 3 is 1/36
Adding these gives 4/36, or one chance in nine (1/9).
2007-06-04 20:15:39
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answer #1
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answered by ignoramus 7
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Hi,
The dice can throw up a number between 1 and 6.
As the dice are distinct, may be colored Red and Blue, or small or big, let us call them D1 and D2.
Foe each value of 1 to 6 of D1, D2 can also have values of 1 to 6. That is there are totally (6 x 6) 36 ways in which the result after rolling can occur.
If the results are (3,6) (4,5) (5,4) (6,3) then sum is 9
(The first number in brackets represent result of D1 and the second one that of D2).
That means there are only four results, which give us a sum of 9 on the dice
Therefore the probability is = 4/36 = 1/9
Good luck
2007-06-04 20:23:41
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answer #2
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answered by sudhakarbabu 3
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36 total possibilities (6 x 6 on each die). 4 possibilities to get a 9 (5-4, 6-3, 4-5, 3-6). So the chances are 4/36 or 1 in 9.
2007-06-04 20:18:16
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answer #3
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answered by TWasserman 2
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4/12 or 1/3
2007-06-04 20:13:18
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answer #4
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answered by rock_teenz 2
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9 can be got in 4 ways
6+3
5+4
4+5
3+6
no. of favourable ways=4
tot. no. of ways=36
probability=4/36=1/9
2007-06-04 20:15:47
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answer #5
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answered by cyberbob 1
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It is less than the probability of you getting a A or a B in that class
2007-06-04 20:22:16
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answer #6
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answered by TheAnswer 2
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This is not the way to do your homework. Rather you should learn to do the problems.
2007-06-04 20:12:10
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answer #7
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answered by Jain 4
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