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suppose a pair of distinct dice is rolled. What is the probability that a sum of 9 shows up

2007-06-04 20:07:17 · 7 answers · asked by diane s 1 in Science & Mathematics Mathematics

7 answers

9 can be obtained by 3 + 6, or 4+5.
The odds of a 3,4,5 or 6 on one die are each 1/6.
The same for the other die.
So the odds of 3 from one and 6 in the other are 1/36, 4 with 5 is 1/36 and 5 with 4 is 1/36 and 6 with 3 is 1/36
Adding these gives 4/36, or one chance in nine (1/9).

2007-06-04 20:15:39 · answer #1 · answered by ignoramus 7 · 0 0

Hi,

The dice can throw up a number between 1 and 6.

As the dice are distinct, may be colored Red and Blue, or small or big, let us call them D1 and D2.

Foe each value of 1 to 6 of D1, D2 can also have values of 1 to 6. That is there are totally (6 x 6) 36 ways in which the result after rolling can occur.

If the results are (3,6) (4,5) (5,4) (6,3) then sum is 9

(The first number in brackets represent result of D1 and the second one that of D2).

That means there are only four results, which give us a sum of 9 on the dice

Therefore the probability is = 4/36 = 1/9

Good luck

2007-06-04 20:23:41 · answer #2 · answered by sudhakarbabu 3 · 0 0

36 total possibilities (6 x 6 on each die). 4 possibilities to get a 9 (5-4, 6-3, 4-5, 3-6). So the chances are 4/36 or 1 in 9.

2007-06-04 20:18:16 · answer #3 · answered by TWasserman 2 · 0 0

4/12 or 1/3

2007-06-04 20:13:18 · answer #4 · answered by rock_teenz 2 · 0 0

9 can be got in 4 ways
6+3
5+4
4+5
3+6
no. of favourable ways=4
tot. no. of ways=36
probability=4/36=1/9

2007-06-04 20:15:47 · answer #5 · answered by cyberbob 1 · 0 0

It is less than the probability of you getting a A or a B in that class

2007-06-04 20:22:16 · answer #6 · answered by TheAnswer 2 · 0 0

This is not the way to do your homework. Rather you should learn to do the problems.

2007-06-04 20:12:10 · answer #7 · answered by Jain 4 · 0 1

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