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how do i get theta?
2007-06-04 17:58:41 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Do you know trig functions? you can use either tangent, sine, or cosine. and you will need to know SOH CAH TOA. It stands for sine equals to opposite side over hypotenuse, cosine equals to adjacent side over hypotenuse, and tangent equals to opposite side over adjacent side. these are just things you need to memorize. oh and a little note.. the adjacent side can never be the hypotenuse... hypotenuse is the longest side of the triangle. So.. don't think that the adjacent side is the hypotenuse and vice versa. Justify the hypotenuse first then the adjacent will be the other side that is close to the angle. So from the top problem.. you should get cos (x)= 5/8 right? then you use calculator and get 51.31781255 right? it shouldnt be hard.. i explained it to you on the other question you asked before.. if you still dont get it then you can always contact me at my email... for the next problem.. the same concept, just different steps. you will use tan (x)=23/21 right? you will get 47.6025622 right?... feel free to email me at mashi_cutie@hotmail.com for further questions on this problem.
2007-06-04 18:06:06 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Right triangle 1: cos theta = side adjacent/hypotenuse = 5/8
so theta = arccos 5/8
Right triangle 2: tan theta = side opposite/side adjacent = 23/21
so theta = arctan 23/21
2007-06-04 18:04:49 · answer #2 · answered by kellenraid 6 · 0⤊ 0⤋
First one,
unknown side = sqrt(8^2-5^2) = sqrt(64-25) = sqrt39
Now, 8/sin 90 = sqrt 39/sin(theta)
so sin theta = sqrt39/8
so theta = arcsin(sqrt39/8)
second one,
unknown side = sqrt(21^2+23^2)
now put the same formula as before
sqrt(21^2+23^2)/sin 90 = 23/ sin theta
2007-06-04 18:09:11 · answer #3 · answered by Mock Turtle 6 · 0⤊ 0⤋
These are both right angle triangles, therefore we know that
x=hypotenuse*cos(theta)
and
x/y=tan(theta)
where x and y are at RIGHT angles to each other.
plug in the numbers and then take the arcsine and arctangent to find theta. Good luck.
2007-06-04 18:08:54 · answer #4 · answered by theanswerman 3 · 0⤊ 0⤋
1. cos(theta) = 5/8 (Adjacent side/hypotenuse)
2. tan(theta) = 23/21 (Opposite side/ Adjaceny side)
2007-06-04 18:06:59 · answer #5 · answered by me_poori 2 · 0⤊ 0⤋
let theta = x
Question 1
cos x = 5 / 8
x = 51.3°
Question 2
tan x = 23 / 21
x = 47.6°
2007-06-05 00:42:08 · answer #6 · answered by Como 7 · 0⤊ 0⤋