Yes, this is a function. You can isolate y to get y=(4-2x)/3.
This could be rewritten as f(x)=(4-2x)/3.
For every x value that you put in, you get a y value.
You could also rewrite it as x=(4-2y)/2, in which case you could have f(y)=(4-2y)/2.
For every y value that you put in, you get an x value.
This constitutes a function.
2007-06-04 17:21:25
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answer #1
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answered by Nick 2
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Yes...it specifies the resulting dependent variable's value with the given independent variable's value.
This is the essence of the mathematical concept of a function. More below.
In this case, either can be the dependent and independent variables, but y is usually the dependent variable.
2007-06-05 00:21:54
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answer #2
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answered by gebobs 6
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yes this is in standard form of a line and a line never has 2 of the same x values with one y so it is a function
2007-06-05 00:27:21
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answer #3
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answered by I love to ball 3
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well, if you put it in slope intercept form
2x+3y=4
3y=-2x+4
y=-2/3x+4/3
which defines a line, and nonvertical lines are indeed functions, so yes!
2007-06-05 00:20:50
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answer #4
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answered by Mike 2
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yes, it is a line of the form
y= -(2/3)*x + (4/3)
-or-
y= m*x+b
justify-
continuous,
only one value of y for every x.
2007-06-05 00:25:30
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answer #5
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answered by anothersnowboarder 3
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Yes, since you can isolate the x and y terms such that you form equations
x = by+c or y = fx+g.
2007-06-05 00:21:40
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answer #6
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answered by cattbarf 7
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