16x^2+80x+100
2007-06-04 17:08:39 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
16x^2 + 80x + 100
= 4 (4x^2 + 20x + 25)
Note that 4x^2 = (2x)^2, 25 = 5^2, and 20x = 2(2x)(5), so we have the form a^2 + 2ab + b^2 = (a+b)^2
= 4 (2x + 5)^2
2007-06-04 17:12:50 · answer #1 · answered by Scarlet Manuka 7 · 0⤊ 0⤋
16x^2 + 80x + 100 = 4(4x^2 + 20 + 25)
= 4(2x + 5)^2
2007-06-04 17:12:47 · answer #2 · answered by mcbrocks 3 · 0⤊ 0⤋
16x^2+80+100=4(4x^2+20x+25)
find the greatest common factor(4)
and than put everything else in the () and make it and equation buy adding its really easy
2007-06-04 17:15:09 · answer #3 · answered by ratmaster199105 2 · 0⤊ 0⤋
16x^2 + 80 x + 100
= (4x)^2 + 2(4x)(10) + (10)^2
= (4x + 10)^2
= (4x + 10)(4x + 10)
= 2(2x + 5) * 2(2x + 5)
= 4(2x + 5)(2x + 5)
2007-06-04 17:15:31 · answer #4 · answered by Akilesh - Internet Undertaker 7 · 0⤊ 0⤋
"Solve" requires an equation with = sign.
Assume that factors are required:-
= 4.(4x² + 20 x + 25)
= 4.(2x + 5).(2x + 5)
2007-06-04 23:47:53 · answer #5 · answered by Como 7 · 0⤊ 0⤋
http://www.webmath.com/
you input the problem, it gives you an answer. this is a great way for checking your work and it is free.
2007-06-04 17:16:14 · answer #6 · answered by blu_drgn25 4 · 0⤊ 0⤋
use a scientific calculator it works for me.
2007-06-04 17:35:30 · answer #7 · answered by william w 5 · 0⤊ 0⤋