5x – 3y = 13
4x – 3y = 11
2007-06-04 15:46:52 · 4 answers · asked by Chris C 1 in Science & Mathematics ➔ Mathematics
5x – 3y = 13 (i)
4x – 3y = 11 (ii)
Multiply (ii) by: -1 & add to (i).
5x - 3y = 13
-4x + 3y = -11
___________
x = 2
Substitute x = 2 into either (i) or (ii) to determine the value for 'y'.
2007-06-04 16:09:22 · answer #1 · answered by S. B. 6 · 1⤊ 0⤋
multiply the second equation by -1 and add to the first equation to get:
(5 + (-4))x - (3 + (-3))y = 13 + (-11)
x = 2
Substitute that into either equation.
4(2) - 3y = 11
8 - 3y = 11
3y = -3
y = -1
2007-06-04 22:53:56 · answer #2 · answered by jcsuperstar714 4 · 0⤊ 0⤋
5x – 3y = 13 ..... (1)
4x – 3y = 11 ..... (2)
(2) * -1,
- 4x + 3y = -11 ..... (3)
Add (1) and (3),
x = 2
Put x = 2 in (1)
10 - 3y = 13
-3y = 3
y = -1
x = 2, y = -1 is the solution
2007-06-04 23:32:09 · answer #3 · answered by Akilesh - Internet Undertaker 7 · 0⤊ 0⤋
5x – 3y = 13 ---(1)
4x – 3y = 11 ---(2)
(1)-(2): x = 2
Sub x=2 into (1): 5(2) - 3y = 13 => -3y = 3 => y = -1
x=2, y=-1
2007-06-04 22:51:11 · answer #4 · answered by Kemmy 6 · 0⤊ 1⤋