This says to write a balanced equation for the complete combustion of each compound. such as:
butene (C4H8)
octane (C8H18)
I was wondering if someone can tell me how to do the first one and I could try the second one. Thanks!
2007-06-04 14:08:10 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
So would this be right for octane:
2C8H18 + 25 O2 --> 18 H2O + 16 CO2
2007-06-04 14:29:32 · update #1
When balancing the combustion reactions of hydrocarbons, you can use the formula:
CxHy + (x + y/4)O2 => xCO2 + (y/2)H2O
2007-06-04 16:57:56 · answer #1 · answered by Michael N 3 · 0⤊ 0⤋
OK. For butene: 1 oxygen must (1) oxidize each C to CO2 and (2) react with 2H to form water. Moreover, oxygen comes as a dimer.
So, 4O2 will handle the C and 2O2 will handle the H. So we can write
C4H8 + 6O2 -> 4CO2 + 4H2O
2007-06-04 14:14:23 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋