10g = 0.01kg. Linear momentum is conserved after bullet has been fired. Let m1=mass of gun, m2 = mass of bullet, v1= final velocity of gun, v2 = final velocity of bullet:
p(before) = p(after). The gun and bullet are initially at rest so p(before) = 0, so
p(after) = o
(m1)(v1) + (m2)(v2) = 0. We want to find v1, solve:
v1 = -(m2)(v2)/(m1)
We can ignore the negative sign as they actually want speed (and not velocity as stated), so substituting values:
v1 = 0.01x500/0.75
v1 = 6.7m/s
2007-06-04 12:04:33
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answer #1
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answered by qspeechc 4
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OK, its been a long time since I have consider this kind of problem, but ... it seems like a common sense ratio. Clearly, the gun's recoil velocity is going to be far less than the forward velocity of the projectile itself; thus, 10 g at 500 m/sec, with 750 g gun mass at Rv velocity. Rv = [(10 g X 500 m/sec.) / 750 g] = 6.7 m/sec.
2007-06-04 13:05:24
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answer #2
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answered by Bob D1 7
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Start with:
Force = Mass x Velocity
So, the force of the bullet is 10g x 500m/sec = 5000 g*m/sec
The force on the gun is the same as the force on the bullet, but now you're solving for the velocity of the gun:
5000 g*m/sec = 750g x V
5000 g*m/sec / 750 g= V
6.7 m/sec = V (answer is D)
2007-06-04 12:03:30
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answer #3
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answered by dbucciar 4
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You need to use conservation of linear momentum. Linear momentum is equal to mass times velocity. The linear momentum of the bullet must equal the linear momentum of the gun.
mv = MV where m is mass of bullet, M is mass of gun, v is velocity of bullet, and V is velocity of gun.
mv/M = V
so (0.010 kg * 500m/s) / 0.750 kg = 6.7 m/s so D is correct.
***FYI***
Force is NOT m*v, it is m*a by Newton's Second Law. It is much easier to use momentum instead of force to find the final velocity of the gun in this problem.
2007-06-04 12:12:49
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answer #4
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answered by msi_cord 7
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Conservation of momentum:
MV = MV (mass of the gun x velocity of the gun) = (mass of the bullet x velocity of the bullet)
(.75 kg) v = .01 kg (500 m/s)
.75 kg (v) = 5 kg-m/s
v = 6.7 m/s
(d)
2007-06-04 12:01:40
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answer #5
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answered by wayne 2
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Wow.... I am sure some is going to give you answer, b/c it is simple. Me being me... use the conservation of momentum and remember before the gun was fired the masses are together and it's velocity is zero.
2007-06-04 11:59:38
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answer #6
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answered by Anonymous
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i've got self belief it is a chemical replace as a results of fact at first the two soltions have been colorless yet whilst mixed at the same time they brought about a chemical reaction which made them turn white. Alsoa powder shaped on the backside which shows some form of ionic bonding befell and probable made a salt
2016-12-12 11:36:22
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answer #7
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answered by kirk 4
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