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47Ca+Sc+?, 235U+4He +?, ?+11B+0-1e, 0-1e+?=40Ar

2007-06-04 08:31:56 · 1 answers · asked by mommy Ty 3 in Science & Mathematics Chemistry

1 answers

47/20 Ca + 41/21 Sc -> 88/41 Nb (Fusion)

235U+4He -> 239/92 Pu (Fusion)

11/4 Be ->11B+0-1e (Beta decay)

0-1e+40/19 K = 40Ar (K e- capture)

2007-06-05 07:18:32 · answer #1 · answered by ag_iitkgp 7 · 0 0

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