if a sphere has a radius of 4cm and a cone's base has a radius of 6cm, and the volume of them are both the same, what is the hight of the cone?
2007-06-04 05:10:22 · 4 answers · asked by Ricky L 1 in Science & Mathematics ➔ Mathematics
**where r= radius, pi = 3.14 and h=height**
volume of a sphere = 4/3piR^3
=4/3*3.14*4^3
=267.95
volume of a cone = 1/3piR^2*h
= 1/3*3.14*6^2*h
=37.68h
since the volume of both are the same
267.95=37.68h
h=7.11cm
2007-06-04 05:13:56 · answer #1 · answered by Anonymous · 0⤊ 1⤋
volume of sphere =volume of cone
4/3piR^3 = 1/3 pi r^2 h
4/3 x pi x 64 = 1/3 x pi x 36 x h
ans a = ans b *h
ans a/ans b=h
use calculater.
my ans came approximately -7.111111
2007-06-04 05:19:01 · answer #2 · answered by cute-goddess 5 · 0⤊ 1⤋
V sphere = 4/3pi(4)^3 = 256pi/3
V cone = 1/3pi6^2h = 12pih
So 12pih = 256pi/3
h = 256/36 = 7.1111 cm
2007-06-04 05:21:57 · answer #3 · answered by ironduke8159 7 · 0⤊ 1⤋
7.111111111 cm
You are asking for the HEIGHT of the cone.
2007-06-04 05:16:07 · answer #4 · answered by Anonymous · 0⤊ 0⤋