Please help with algebra!?

Question

(t^2+12t+36) divided by (t+9)

Answer 1

first factor (t^2+12t+36)
(t^2+12t+36)
= t^2 + 6t + 6t + 36
= t(t + 6) + 6(t + 6)
= (t + 6)(t + 6) = (t + 6)^2

Therefore (t^2+12t+36) /(t+9)
= (t + 6)^2/(t + 9)

Answer 2

(t^2 + 12t + 36) = ( t + 6) ( t + 6) then divided by ( t + 9 )

= ( t + 6) ( t + 6) / ( t + 9 )

Answer 3

first factor t^2+12t+36
(t+3)(t+9)
then divide by (t+9) and they cancel out
=t+3

Answer 4

factoring the numerator would not give you a factor that would cancel t+9.

So, dividing directly would look like this: (You will need to move like terms below each other as Answers would not allow for spacing to take place)

t + 3
_______________________
t+9 I t^2 + 12t + 9
- t^2 - 9t
---------------------------------------
3t + 9
-3t - 27
---------------------------------------
-18

Thus, the quotient would be t+3 R -18

Answer 5

Assume that question should read as:-
(t² + 13t + 36) / (t + 9)
= (t + 9).(t + 4) / (t + 9)
= t + 4

Answer 6

i think that after dividing the qouitient may be t+3 and remainder may be 9 i think mine is right