(√3-√2)(√3+√2)?

Question

simplify this please do you need to ±

Answer 1

(√3-√2)(√3+√2)

Here, we want to FOIL it.
F irsts
O utsides
I nsides
L ast

so in (√3-√2)(√3+√2), first we multiply √3 and √3 to get √9, or 3. Then we multiply √3 and √2. Next we multiply -√2 and √3. Last we multiply -√2 and √2.

So we have
√9+√6-√6-√4

Simplify.
√9=3 and √4=2
3+√6-√6 -√4

As you see, the √6 and the -√6 can cancel.

So we end up with,
3-2, or 1.

This (√3-√2)(√3+√2) is called difference of squares. Difference of squares is:
a^2-b^2=(a+b)(a-b)

Answer 2

= 3 + √6 - √6 - 2
= 1

Answer 3

this is of the form a^2-b^2 = (a+b)(a-b)
so (√3)^2-(√2)^2
= 3-2 =1

Answer 4

Do you recognize the form (a - b)(a + b)? It's the difference of two squares! In this case the squares are 3 and 2. The expanded form is 3 - 2, which evaluates to 1.

Answer 5

Use the following formula to simplify:

(a^2 - b^2) = (a+b) * (a-b)

Answer 6

(a - b) (a + b) = a^2 - b^2 is the formula to apply here.

3 - 2 = 1

Answer 7

Multiply each piece out:

sqrt(3)*sqrt(3) + sqrt(3)*sqrt(2) - sqrt(2)*sqrt(3) -
sqrt(2)*sqrt(2) =

3+sqrt(6)-sqrt(6)-2 = 3-2 = 1

Answer 8

(a+b)(a-b) = a^2 - b^2
here a = sqrt 3 and b = sqrt 2

so,
(sqrt 3 - sqrt 2)(sqrt3 + sqrt 2)
(sqrt 3)^2 - (sqrt 2)^2
3 - 2 = 1

Answer 9

Because (x-y)(x+y)=x^2-y^2

(rt3-rt2)(rt3+rt2)
(rt3)^2)-(rt2^2)
(3)-(2)
=1

Answer 10

1 or .099999998