PLEASE HURRY help PLEASE?

Question

The length of a rectangle is 2 more than twice its width. The area of the rectangle is 60 square units. What is the width of the rectangle?
A) 12 units

B) 17 units

C) 6 units

D) 5 units

Answer 1

D
5*2+2=12
12*5=60

Answer 2

Answer is D) 5 units.
How I arrived at this answer:
Let the width be x.
Let the lenth by 2x + 2.
So the area is x(2x +2) = 60
You can solve this as you solve quadratic equations.
The answe you'll get for x is 5 and -6.
-6 is impossible for the width, so the answer is 5 units.
Hope this helps.

Answer 3

let b=x

l=2x+2

2(2x+2)=60

2x^2+2x-60=0

x^2+x-30=0

(x+6)(x-5)

x=5 units

Answer 4

x(2x+2)=60

2x^2+2x-60=0

2(x^2+x-30)=0

2(x+6)(x-5)=0

x=5 and -6

since width can't be negative the answer is d. 5

Answer 5

l=2+2w
A=l*w

60=(2+2w)*w
60=2w+2w^2 (divide all by 2)
30=w+w^2
0=w^2+w-30
0=(w+6)(w-5)
w=-6 or 5
since width is not negative, the width is 5 - answer D

Answer 6

width is the unknown (x)

A(rectangle) = length x width
60 = (2x+2)(x)
60 = 2x^2 + 2x
30 = x^2 + x
0 = x^2 + x - 30
0 = (x - 6)(x + 5) ----------> x = 6 or -5

So, x = 6 units --------> C

Answer 7

D x * (2x+2) = 60.........2x^2+ 2x - 60 = 0
( x - 5 )(2 x +12 ) = 0 ....x=5

Answer 8

D

60=(2x+2)(x)
60=2x^2+2x
30=x^2+x
30=25+5

SO x must = 5.

Answer 9

let width = w
length = 2w + 2
w.(2w + 2) = 60
2w² + 2w - 60 = 0
w² + w - 30 = 0
(w + 6).(w - 5) = 0
w = 5
ANSWER D)

Answer 10

I think it's A